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Mnenie [13.5K]
3 years ago
5

How to solve 6x-9=8x+11

Mathematics
2 answers:
vredina [299]3 years ago
6 0
6x-9=8x+11
-6x -6x
-9=2x+11
-11. -11
-20=2x
2. 2
-10=x
fenix001 [56]3 years ago
4 0
6X-9=8X+11
-6x -6x
___________
-9= 2X+11
-11 -11
___________
-20=2X
% %
2 2
__________
-10=x


So the answer is x=-10
I tried to make is easier for you to understand. (;
Hope it helped.

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The sum of two positive integers, a and b, is at least 30. The difference of the two integers is at least 10. If b is th
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Answer:

a + b \geq 30

b - a \geq 10

Step-by-step explanation:

Given

The sum of the two positive integer a and b is at least 30, this means the sum of the two positive integer is 30 or greater than 30, so we write the inequalities as below.

a + b \geq 30

The difference of the two integers is at least 10, if b is the greater integer then we subtract integer a from integer b, so we write the inequality as below.

b - a \geq 10

Therefore, the following system of inequalities could represent the values of two positive integers a and b.

a + b \geq 30

b - a \geq 10

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Given the vectors, a=3i+4j, b=-2i+5j, c=10i-j, d=-1/3i+5/2j, find -0.4a-0.3b+0.2d=?
sveta [45]

Answer:

-\frac{2}{3}i - \frac{13}{5}j

Step-by-step explanation:

-0.4(3i + 4i) - 0.3(-2i + 5j) + 0.2(-\frac{1}{3}i + \frac{5}{2}j)

-1.2i - 1.6j + 0.6i - 1.5j - \frac{0.2}{3}i + 0.5j

Converting to fraction form;

-\frac{6}{5}i + \frac{3}{5}i - \frac{1}{15}i - \frac{8}{5}j - \frac{3}{2}j + \frac{1}{2} j

<u>Solving the i part;</u>

\frac{-18i + 9i - i}{15} = -\frac{2}{3}i

<u>Solving the j part;</u>

\frac{-16j-15j+5j}{10} = -\frac{13}{5}j

So -0.4a - o.3b + 0.2d =  -\frac{2}{3}i - \frac{13}{5}j

6 0
3 years ago
The equation y = 0.75x + 10 describes the cost, y, of placing an ad with x words in the classified section of a newspaper. How m
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y = cost = $25

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15=0.75x

x = 15/0.75 = 20

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6 0
3 years ago
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