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kifflom [539]
3 years ago
10

Jeremiah, Leah and Pascal are sharing a gift and each contributes $12. If Ebenzer agrees to contribute as well and all four pay

and equal amount for the same gift, how much does each person pay?
{The answer key says 3, and I'm confused as why it is.}
Mathematics
2 answers:
Pani-rosa [81]3 years ago
7 0
Well, 4 people are each paying the same amount... the price they are all paying together is $12... basically, do 12 / 4, and you get three. 

olchik [2.2K]3 years ago
6 0
Well, there are four people that are going to pay the same amount. and twelve divided by four is three.
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Use an addition or subtraction formula to find the exact value of the expression, as demonstrated in example 1. tan(105°)
strojnjashka [21]
Use an addition or subtraction formula to find the exact value of the expression, as demonstrated in example 1. tan(105°)

7 0
3 years ago
I could use some help doing this simple math problem lol.
alexira [117]
D:k-9\geq 0 \wedge k\geq0\\
D:k\geq 9 \wedge k\geq0\\
D:k\geq 9\\
\sqrt{k-9}-\sqrt k=-1\\
\sqrt{k-9}=-1+\sqrt k\\
k-9=(-1+\sqrt k)^2\\
k-9=1-2\sqrt k+k\\
2\sqrt k=10\\
\sqrt k =5\\
k=25


7 0
2 years ago
1) find the equation of the line parallel to
In-s [12.5K]

<u>Answer:</u>

1) The equation of the line parallel to  x-5y=6 and through (4,-2) is 5y = x -14

2) The equation of the line perpendicular to y= -2/5x + 3 and through (2,-1) is  2y = 5x -12

<u>Solution:</u>

<u><em>1) find the equation of the line parallel to  x-5y=6 and through (4,-2).</em></u>

Given, line equation is x – 5y = 6  

We have to find the line equation that is parallel to given line and passing through the point (4, -2)

Now, let us find slope of the given line.

\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-1}{-5}=\frac{1}{5}

Now, we know that, slope of parallel lines are equal.

So, slope of required line is 1/5 and it passes through (4, -2)

Now, using point slope form

y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on line. }

y-(-2)=\frac{1}{5}(x-4) \rightarrow 5(y+2)=x-4 \rightarrow 5 y+10=x-4 \rightarrow x-5 y=14

Hence, the line equation is 5y = x -14

<u><em> 2) find the equation of the line perpendicular to y= -2/5x + 3 and through (2,-1)</em></u>

\text { Given, line equation is } y=-\frac{2}{5} x+3 \rightarrow 5 y=-2 x+15 \rightarrow 2 x+5 y=15

We have to find the line equation that is perpendicular to given line and passing through the point (2, -1)

Now, let us find slope of the given line.

\text { Slope }=\frac{-x \text { coefficient }}{y \text { coefficient }}=\frac{-2}{5}=-\frac{2}{5}

Now, we know that, product of slopes of perpendicular lines equals to -1.

So, slope of required line \times slope of given line = -1

slope of required line = -1 \times \frac{5}{-2}=\frac{5}{2}

And it passes through (2, -1)

Now, using point slope form

\begin{array}{l}{\text { Line equation is } y-(-1)=\frac{5}{2}(x-2) \rightarrow 2(y+1)=5(x-2)} \\\\ {\rightarrow 2 y+2=5 x-10 \rightarrow 5 x-2 y=12}\end{array}

Hence, the line equation is 2y = 5x -12

4 0
3 years ago
State the x- and y-intercepts.
Rufina [12.5K]

1. Y-Intercepts are where the graph crosses the y-axis. For a parabola, this occurs once, at (0, -3) in the graph shown.

2. X-Intercepts are where the graph crosses the x-axis. For a parabola, this occurs twice, at (-1, 0) and (3, 0) in the graph shown.

3. A parabola that is positive opens upwards, while a parabola that is negative opens downwards. Therefore, this parabola is positive.

Hope this helps!! :)

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2 years ago
An airplane was moving 1200 km per minute
Aleksandr-060686 [28]

Answer:

Its velocity was 20 km/s southward  

Step-by-step explanation:

3 0
3 years ago
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