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bekas [8.4K]
3 years ago
8

According to the fundamental theorem of algebra how many roots exist for the polynomial function f(x)=8x^7-x^5+x^3+6

Mathematics
2 answers:
antiseptic1488 [7]3 years ago
8 0

Answer: There are 7 roots for the polynomial function.

Step-by-step explanation:

Since we have given that

f(x)=8x^7-x^5+x^3+6

We need to find the number of roots exist for the polynomial.

As we know that

Number of roots = Highest degree of the polynomial.

So, the number of roots = 7

Hence, there are 7 roots for the polynomial function.

mojhsa [17]3 years ago
5 0

Answer:

7

Step-by-step explanation:

This is a 7th degree polynomial.  There should be 7 roots.  Note how degree of poly = number of roots.

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Answer:

x=2, y=13

Step-by-step explanation:

In order to get this by addition which is the easiest way for this you want to take both equations

y=3x+7 and y=-4x+21 and move x to the other side of the equation so it is like  4x+y=21 and -3x+y=7 like that now you have to get rid of one of the exponents and the easiest one to get rid of is y so I'm going to multiply -3x+y=7 by negative 1 so it becomes 3x-y=-7 that way the equations value has not changed since I multiplied both sides and now when I add

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