(2-7m^6)^2
rearrange terms:
(2-7m^6)^2
(-7m^6 + 2)^2
expand the squares:
(-7m^6 + 2)^2
(-7m^6 + 2)(-7m^6 + 2)
distribute:
(-7m^6 + 2)(-7m^6 + 2)
-7(-7m^6 + 2) • m^6 + 2(-7m^6 + 2)
distribute:
-7(-7m^6 + 2) • m^6 + 2(-7m^6 + 2)
49m^12 - 14m^6 + 2(-7^6 +2)
distribute:
49m^12 - 14m^6 + 2(-7^6 +2)
49m^12 - 14m^6 - 14m^6 + 4
combine like terms:
49m^12 - 14m^6 - 14m^6 + 4
49m^12 - 28m^6 + 4
solution:
49m^12 - 28m^6 + 4
please mark brainliest and hope it helps
Answer:
cautousness because he is aware of his surroundings
Answer:
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Step-by-step explanation:
I'm sure you are familiar with the product rule,
If y = u*v => dy/dx = u * dv/dx + v * dy/dx <----- product rule
In this case:

Now remember the sum rule:

For this second bit we apply the chain rule:

If we substitute these values back into the expression...
...we get the following:

The rest is just pure simplification:

Now let's equate this to equal 8 for the second bit and solve for x:

Answer
do u have a demonstration
picture
Step-by-step explanation:
Sqrt of 56 is about 7.5
So 6 would be in the first blank and 8 would be in the second blank.
6,7,8 are consecutive