We can already tell if a quotient is negative if the divisor or the dividend is a negative number. (Only 1 negative number and 1 positive number, because if there are two negative numbers then the outcome will be a positive.)
Question 4 has one negative number in it so it's already visible that the quotient is already negative. And if we did divide it the answer will be -1.
Question 3 has two negative numbers so we know that the outcome is a positive number. If solve the quotient is 0.023931813 which is clearly not a negative number.
Question 2 has one negative number so the answer will be negative. The quotient will be -23.80952381, which is clearly a negative number.
Question 1 doesn't have any negative numbers so the outcome will also be a positive number. The quotient for question 1 is 0.231578947.
So questions 2 and 4 both have negative quotients. While, questions 1 and 3 have positive quotients.
To get the total amount of fans that attended the game, add 77,098 and 3,397 together.
1 1 1
77,098
+ 3,397
______
80,495
80,494 total fans attended the game altogether.
Answer:
C=14
Step-by-step explanation:
To find the minimum value, graph each of the inequalities. After graphing each inequality, test a point and shade the region that satisfies the inequality. Once all inequalities have been shaded, find the region where they all overlap. The region will be bounded by intersection points. Test each of these points into C=x+3y. The least value for C is the minimum.
(14,0) (0,17.5) (3.08,3.64)
C=14+3(0) C=0+3(17.5) C=3.08 + 3(3.64)
C=14 C=52.5 C=14
Answer: Choice D 
Reason:
74% = 0.74 represents the probability of him making any given free throw.
This means 1 - 0.74 is the probability of him missing.
Getting four misses in a row has a probability of (1-0.74)^4 which is the same as writing 
In other words, we multiply exactly four copies of (1-0.74) to get our answer.
Answer:
That's an isosceles right trapezoid. The legs equal hypotenuse * (1 / sq root (2))
legs = 7 * 1 / sqroot (2)
Answer is D
Step-by-step explanation: