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Oxana [17]
3 years ago
10

Values of x in the equation 10x^2-64=36+6x^2

Mathematics
1 answer:
NISA [10]3 years ago
5 0
10x^2-6x^2 = 4x^2
-64-36 = 100
4x^2 -100 = 0
(2x -10)(2x+10)
X = 2/10 and x = - 2/10
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A rectangular parking lot has a perimeter of 384 meters. The length of the parking lot is 36 meters less than the width. Find th
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Answer:

The length and width of the parking lot is 78 meters and 114 meters respectively.

Step-by-step explanation:

Given;

Perimeter of the parking lot = 384\ m

Solution,

Let the width of the parking lot be x.

Then, according to question length = (x-36).

The perimeter of a rectangle is sum of all the sides of rectangle. Which is given by an expression;

perimeter=2\times(length+width)

Now substituting the values, we get;

384=2\times(x-36+x)\\\frac{384}{2}=(2x-36)\\192=2x-36\\192+36=2x\\2x=228\\x=\frac{228}{2}= 114

Width = 114\ m

Length = x-36=114-36=78\ m

Hence the length and width of the parking lot is 78 meters and 114 meters respectively.

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Find the ratio of the area inside the square but outside the circle to the area of the square
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