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3 years ago

8. What is the measure of ZACB ? 50 points^^

Mathematics

2 answers:

miss Akunina [59]3 years ago

7 0

$Question$

What is the measure of ZACB ?

Answer:

Your Answer Would be 90° Or 180° My friend!

A triangle's angles add up to 180 degrees because one exterior angle is equal to the sum of the other two angles in the triangle.

Hope this Helps!!!

$xXxAnimexXx$

Verizon [17]3 years ago

5 0

Answer:

$for \: clear \: the \: answer \: \\ refer \: the \: attach ment \\ < cba = 180 - 70 = 110(angle \\ \: of \: a \: line \: = 180) \\ we \: want \: to \: find \: < acb \\ we \: have \: sum \: of \: angle \: in \: \: a \: triangle \: = 180 \\ so \: let < acb = x \\ then \\ 20 + 110 + x = 180 \\ 130 + x = 180 \\ x = 180 - 130 \\ x = 50 \\ thank \: you$

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3 years ago

I need help fast what is 9m−(3+7m) simplified?

iogann1982 [59]

Answer:

Simplifying 9m + -3 + -7m = 0

Reorder the terms: -3 + 9m + -7m = 0

Combine like terms: 9m + -7m = 2m -3 + 2m = 0 Solving -3 + 2m = 0

Solving for variable 'm'. Move all terms containing m to the left, all other terms to the right.

Add '3' to each side of the equation. -3 + 3 + 2m = 0 + 3 Combine like terms: -3 + 3 = 0 0 + 2m = 0 + 3 2m = 0 + 3 Combine like terms: 0 + 3 = 3 2m = 3

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Step-by-step explanation:

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3 years ago

The vertices of ∆ABC are A(-2, 2), B(6, 2), and C(0, 8). The perimeter of ∆ABC is units is? What is the area?

11111nata11111 [884]

we have

$A(-2, 2),B(6, 2),C(0, 8)$

see the attached figure to better understand the problem

we know that

The perimeter of the triangle is equal to

$P=AB+BC+AC$

and

the area of the triangle is equal to

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB\\heigth=DC$

we know that

The distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Step $1$

Find the distance AB

$A(-2, 2),B(6, 2)$

Substitute the values in the formula

$d=\sqrt{(2-2)^{2}+(6+2)^{2}}$

$d=\sqrt{(0)^{2}+(8)^{2}}$

$dAB=8\ units$

Step $2$

Find the distance BC

$B(6, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-6)^{2}}$

$d=\sqrt{(6)^{2}+(-6)^{2}}$

$dBC=6\sqrt{2}\ units$

Step $3$

Find the distance AC

$A(-2, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0+2)^{2}}$

$d=\sqrt{(6)^{2}+(2)^{2}}$

$dAC=2\sqrt{10}\ units$

Step $4$

Find the distance DC

$D(0, 2),C(0, 8)$

Substitute the values in the formula

$d=\sqrt{(8-2)^{2}+(0-0)^{2}}$

$d=\sqrt{(6)^{2}+(0)^{2}}$

$dDC=6\ units$

Step $5$

Find the perimeter of the triangle

$P=AB+BC+AC$

substitute the values

$P=8\ units+6\sqrt{2}\ units+2\sqrt{10}\ units$

$P=22.81\ units$

therefore

The perimeter of the triangle is equal to $22.81\ units$

Step $6$

Find the area of the triangle

$A=\frac{1}{2}*base *heigth$

in this problem

$base=AB=8\ units\\heigth=DC=6\ units$

substitute the values

$A=\frac{1}{2}*8*6$

$A=24\ units^{2}$

therefore

the area of the triangle is $24\ units^{2}$

4 0

3 years ago

Read 2 more answers

Can someone please help me with that one problem!

maks197457 [2]

Answer:

AAS method can be used to prove that the two triangles are congruent.

Step-by-step explanation:

According to the question for the two triangles one pair of opposite angles are equal. One another pair of angles are equal for the two and one pair of sides are also equal of the two.

Hence, the two given triangles are congruent by AAS rule.

Hence, AAS method can be used to prove that the two triangles are congruent.

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4 years ago

GIVING BRAINLEST TO THE PERSON WHO ANSWERS IT FIRST AND CORRECT!!

Kruka [31]

Answer:

read below explanation

Step-by-step explanation:

KEY= C;CAROL T;TINO B;BAXTER

inches: C=90 T=90 B=90

Feet: C=7.5 T=7.5 B=7.5

Yards C=2.5 T=2.5 B=2.5

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3 years ago