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2 years ago

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in 1992 Jason bought a gallon of gas for$1.22 yesterday he bought a gallon of gas for$2.18 what is the percentage increase of th

e price of a gallon of gas from 1992 to yesterday if necessary round to the nearest tenth of percent

2 answers:

sergeinik [125]2 years ago

7 0

<h2>Greetings!</h2>

Answer:

The percentage increase is 78.68%!

Step-by-step explanation:

To find the percentage increase, firstly you need to find the difference in the two values:

2.18 - 1.22 = 0.96

Then simply divide the difference by the original amount:

0.96 ÷ 1.22 = 0.7868

Multiply by 100 to get a percentage:

0.7868 x 100 = 78.68

So the percentage increase is 78.68%!

<h2>Hope this helps!</h2>

Stels [109]2 years ago

4 0

Answer:

The percentage increase of the price of a gallon of gas from 1992 to yesterday is 78.7%.

Step-by-step explanation:

Consider the provided information.

In 1992 Jason bought a gallon of gas for$1.22

Yesterday he bought a gallon of gas for$2.18

The increment in price can be calculated as:

$\$ 2.18-\$ 1.22= \$ 0.96$

We need to calculate the percentage increase of the price of a gallon of gas from 1992 to yesterday.

Which can be calculated as shown below:

$\frac{0.96}{1.22}\times 100$

$0.7868\times 100$

78.68%

Round to the nearest tenth of percent 78.7%.

Hence, the percentage increase of the price of a gallon of gas from 1992 to yesterday is 78.7%.

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Ivanshal [37]

Answer:

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Step-by-step explanation:

For this case we know the following propoertis for the random variable X

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We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

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With:

$\mu_{\bar X}= 83$

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Part b

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$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

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Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

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