Hip Breadths and Aircraft Seats
Engineers want to design seats in commercial aircraft so that they are wide enough to fit 98% of all males. (Accommodating 100% of males would be too expensive.) Men have hip breadths that are normally distributed with a mean of 14.4 in. and a standard deviation of 1.0 in. Find P 98. That is, find the hip breadth for men that separates the smallest 98% from the largest 2%.
Answer:
2.14
Step-by-step explanation:
2.14x24=51.36
Answer:
2y-8
-Step-by-step explanation:
2y +4y = 2y
so
2y - 8
Ur outlier is 22....so we will remove it.
now we find the mean (average) of the data set...
(9+4+10+9+5+2+10+3+3+5) / 10 = 60/10 = 6...this is ur mean
now we subtract the mean from every data value...and find its absolute value
9 - 6 = 3....| 3| = 3
4 - 6 = -2...|-2| = 2
10 - 6 = 4..|4| = 4
9 - 6 = 3....|3| = 3
5 - 6 = -1..|-1| = 1
2 - 6 = -4...|-4| = 4
10 - 6 = 4..|4| = 4
3 - 6 = -3...|-3| = 3
3 - 6 = -3...|-3| = 3
5 - 6 = -1...|-1| = 1
now we find the mean (average) of these numbers...that is ur MAD
(3+2+4+3+1+4+4+3+3+1) / 10 = 28/10 = 2.8
ur answer : on average, the height of the plant varies 2.8 inches from the mean of 6 inches
What is the constant of proportionality for the relationship shown in the table? x 2 4 6 8 y 1 2 3 4
☆☆☆☆☆☆1/2
2
4
8
Y=kx where k is the constant proportionality
y=kx
(1)=k(2)
1/2=k2/2
1/2=k
