X³ = 125/27
Cube root both sides to isolate the variable:
∛x³ = ∛(125/27)
x = ∛(125/27)
∛125 = 5, ∛27 = 3
x = 5/3
So u already know that the radius is half of the circle which in this case is 28 mm. And both circles at the top touch both sides of the rectangle.
Process:
28x4=112.
This is the top side, but because you could fit 2 circles at the top and you know the measurement, it is common sense to think that it would be the same on the other side. So the area of the square/ rectangle:
112x112= 12,534 mm
That would be a right-angled triangle.
Answer:
Step-by-step
Monthly Payment $1,088.41
Total Interest Paid $1,121.77
Total Paid $26,121.77
Mark brainliest if this answer is correct please
Answer:
not possible.
Step-by-step explanation:
number of invitations luanne has to address after x days = 120-15x
number of invitations Darius has to address after x days = 120 + 15(7-x)
so, if the number of invitations should be the same for both of them,
we have to equate their number of invitations
120-15x = 120 + 15(7-x)
subtracting 120 from both the sides,
-15x = 15(7-x) = 105 -15x
adding we 15x on both sides, we wont find any solution for x.
so, this isnt possible or the question must be wrong.
