Answer:
Part A: 40% are pennies
Part B: NIckels 10, Quarters 20, Pennis 20
To solve this problem, you must find a common denominator. First, you multiply the denominators together, then, multiply the numerator of the first fraction by the original denominator of the second fraction and vis-versa.
<span>3*4 = denominator of both
</span><span>2*4 = numerator of first fraction
</span><span>3*3 = numerator of second fraction
</span>
Your fractions should end up being 8/12 cups of raisins and 9/12 cup of almonds. You can now compare these fractions.
<span>Overall, there are 1/12 more almonds than raisins.</span>
Answer:
The answer to your question is y = -5x + 32 point-slope form
5x + y - 32 = 0 general form
Step-by-step explanation:
Data
(8, -8)
⊥ x - 5y - 6 = 0
Process
1.- Get the slope of the line given
x - 5y - 6 = 0
-5y = -x + 6
y = -x/-5 + 6/-5
y = x/5 - 6/5
slope = 1/5
slope of the new line -5, because the lines are perpendicular
2.- Get the equation of the new line
y - y1 = m(x - x1)
y + 8 = -5(x - 8)
y + 8 = -5x + 40
y = -5x + 40 - 8
y = -5x + 32 point-slope form
Equal to zero to find the general form
5x + y - 32 = 0 general form
We have the frequencies for each of the grades. We can estimate the number of students graded by adding all those frequencies. Let's call N the total number of grades:
We have then a total number of grades of 39.
The corresponding relative frequency for a grade is the ratio of the frequency to the total number of "samples", 39 in this case.
Then, for grade A, the relative frequency (RF) will be:
This will be the fraction of the total grades that are A. Represented as a percentage will be 10.26%, rounded to two decimal places.
Now, to complete the table we do the same for the other frequencies:
For grade B:
For grade C:
For grade D:
For grade F: