A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 97m long and 76m wide. F

Question

2 years ago

6

ind the area of the training field. Use the value 3.14 for pie , and do not round your answer. Be sure to include the correct unit in your answer.

1 answer:

sasho [114] · Answer 1 · 2022-12-19T17:06:32+03:00

If the radius of the semi-circle is 38 m. Then the area of the training field will be 11,908.459 square meters.

<h3>What is Geometry?</h3>

It deals with the size of geometry, region, and density of the different forms both 2D and 3D.

A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 97 m long and 76 m wide.

Then the radius of the semi-circle will be

2r = 76

r = 38 m

Then the area of the training field will be

Area = area of rectangle + 2 x area of semi-circle

Area = 97 x 76 + 2 x (1/2) x π x 38²

Area = 7372 + 4536.459

Area = 11908.459 square m

More about the geometry link is given below.

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