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defon
3 years ago
12

the black triange in the first quadrant is the original figure label each other triangle with its transformation PLS HELP ASAP 6

0 POINTS PLEASE HELP ASAP

Mathematics
1 answer:
Olenka [21]3 years ago
4 0

Answer:

Step-by-step explanation:

Transformation from figure 1 to figure 2,

Translation of figure 1 by 6 units to the left.

Transformation of figure 1 to figure 3,

Reflection of figure 1 across y-axis.

Transformation from figure 1 to figure 4,

Translation of figure 1 by 6 units to the left and 4 units down.

Transformation from figure 1 to figure 5,

Translation of figure 1 by 3 units left and 6 units down.

Transformation from figure 1 to figure 6,

Reflection of figure 1 across x-axis.

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Need answer ASAP <br> *MARKING BRAINLIEST
NikAS [45]

Answer:

an = 4n +5

Step-by-step explanation:

First we need to find a common difference

d = a2-a1 = 13-9 = 4

The formula for an

an =a1+d(n-1)

an = 9 + 4(n-1)

Distributing

an = 9+4n-4

Combine like terms

an = 4n +5

8 0
3 years ago
Whats the greatest common factor of 18 and 27 and 54
vodomira [7]

Answer: 9

Step-by-step explanation:

From doing the math I think it should be 9

7 0
3 years ago
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A bakery sells ,medium and large pies. The ratio small:medium:large is 3:5:2 .What fraction of the pies are large ?
SOVA2 [1]
2/8

there’s 8 total pies and among all of them, there’s only 2 large pies
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6 0
2 years ago
Use the Newton-Raphson method to find the root of the equation f(x) = In(3x) + 5x2, using an initial guess of x = 0.5 and a stop
xxMikexx [17]

Answer with explanation:

The equation which we have to solve by Newton-Raphson Method is,

 f(x)=log (3 x) +5 x²

f'(x)=\frac{1}{3x}+10 x

Initial Guess =0.5

Formula to find Iteration by Newton-Raphson method

  x_{n+1}=x_{n}-\frac{f(x_{n})}{f'(x_{n})}\\\\x_{1}=x_{0}-\frac{f(x_{0})}{f'(x_{0})}\\\\ x_{1}=0.5-\frac{\log(1.5)+1.25}{\frac{1}{1.5}+10 \times 0.5}\\\\x_{1}=0.5- \frac{0.1760+1.25}{0.67+5}\\\\x_{1}=0.5-\frac{1.426}{5.67}\\\\x_{1}=0.5-0.25149\\\\x_{1}=0.248

x_{2}=0.248-\frac{\log(0.744)+0.30752}{\frac{1}{0.744}+10 \times 0.248}\\\\x_{2}=0.248- \frac{-0.128+0.30752}{1.35+2.48}\\\\x_{2}=0.248-\frac{0.17952}{3.83}\\\\x_{2}=0.248-0.0468\\\\x_{2}=0.2012

x_{3}=0.2012-\frac{\log(0.6036)+0.2024072}{\frac{1}{0.6036}+10 \times 0.2012}\\\\x_{3}=0.2012- \frac{-0.2192+0.2025}{1.6567+2.012}\\\\x_{3}=0.2012-\frac{-0.0167}{3.6687}\\\\x_{3}=0.2012+0.0045\\\\x_{3}=0.2057

x_{4}=0.2057-\frac{\log(0.6171)+0.21156}{\frac{1}{0.6171}+10 \times 0.2057}\\\\x_{4}=0.2057- \frac{-0.2096+0.21156}{1.6204+2.057}\\\\x_{4}=0.2057-\frac{0.0019}{3.6774}\\\\x_{4}=0.2057-0.0005\\\\x_{4}=0.2052

So, root of the equation =0.205 (Approx)

Approximate relative error

                =\frac{\text{Actual value}}{\text{Given Value}}\\\\=\frac{0.205}{0.5}\\\\=0.41

 Approximate relative error in terms of Percentage

   =0.41 × 100

   = 41 %

7 0
2 years ago
The mean price for used cars is $10,550. A manager of a Kansas City used car dealership reviewed a sample of 50 recent used car
Evgen [1.6K]

Answer:

go to algebra answers.com

Step-by-step explanation:

8 0
2 years ago
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