20% of a number is 16. What is 50% of the same number?

Hannah is saving money for a car. She earns $160 each week working part time after school and on the weekends at Papa's Pizza. H

Yuliya22 [10]

From the problem we know that Hanna saves one-half of her paycheck each week, so she saves $( \frac{1}{2})(160)= \frac{160}{2} =80$ . Also, we know that her parents put $50 in her savings account each week, so the total amount she and her parents put in her saving's account is $80+50=130$ .
Since we know that Hanna currently has <span>$1,280 in her saving's account and each week she and her parents deposit $130 to the account, with </span> $n$ representing the number of weeks, we can model the situation as follows:
$f(n)=1280+130n$

3 0

4 years ago

Read 2 more answers

Please help me :( I’m struggling

QveST [7]

Answer:

im assuming its b because the quality for the pic is bad and i cant really see it

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

John and Jane are married. The probability that John watches a certain television show is .7. The probability that Jane watches

ikadub [295]

a) The probability that both John and Jane watch the show is 0.12.

b.The probability that Jane watches the show, given that John does is 0.1714.

c)They do watch show independent of each other.

Step-by-step explanation:

Here, as given in the question:

Probability that John watches a certain show = 0.7 ⇒ P(J) = 0.7

Probability that Jane watches a certain show = 0.3 ⇒ P(Je) = 0.3

Probability that John watches a certain show given Jane watches it to

= 0.4 ⇒ P(J/Je) = 0.4

a. ) Here, we need to find the probability of both Jane and John watching a show , P(J∩Je)

Now, by BAYES THEOREM:

$P(J/Je) = \frac{P(J \cap Je)}{P(Je)}$

$\implies 0.4 = \frac{P(J \cap Je)}{0.3} \\\implies P(J \cap Je) = 0.4 \times 0.3 = 0.12$

Hence the probability that both John and Jane watch the show is 0.12.

b.) The probability that Jane watches the show, given that John does is P(J/Je)

By BAYES Theorem:

$P(Je/J) = \frac{P(J \cap Je)}{P(J)}\\\implies P(Je/J) = \frac{0.12}{0.7} = 0.1714$

Hence, the probability that Jane watches the show, given that John does is 0.1714.

c) As we can see P(Jane ∩ John) = 0.12

So, the probability of both of them seeing the show TOGETHER is 0.12.

Hence, they do watch show independent of each other and the probability of doing that is 1.0.12 = 0.88

7 0

3 years ago

The diagram below shows the dimensions of Tessa’s garden.

Leona [35]

Answer:

Tessa's mistake was to have multiplied each dimension by two instead of multiplying by a square root of two.

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z -----> the scale factor

x ----> the area of the enlarged garden

y ----> the area of the original garden

$z^{2}=\frac{x}{y}$

we have that

If Tessa multiplies each dimension by 2, then the scale factor equals 2.

$z=2$

substitute

$2^{2}=\frac{x}{y}\\\\ 4=\frac{x}{y}\\\\x=4y$

The area of the enlarged garden will be equal 4 times the area of the original garden

so

If Tessa wanted to have twice as much surface, she must multiply each dimension by a square root of 2.

therefore

Tessa's mistake was to have multiplied each dimension by two instead of multiplying by a square root of two

8 0

3 years ago

6|y+1|=60 what the answer

san4es73 [151]

The answer should be y=9 and y=-11

4 0

3 years ago