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3 years ago

Please see attachment

Mathematics

1 answer:

LuckyWell [14K]3 years ago

7 0

The difference between the means is about 5 times

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14 to 35 simplest form

Llana [10]

14:35 is a ratio, and of-coarse, as we know, we can transform that into another way of writing a ratio:

14/35

Simplify

14/7 = 2
35/7 = 5

2:5

Answer: 2 to 5

3 0

3 years ago

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If a cylinder has a height of 10cm and a radius of 2.5cm then whats the surface area and the volume?

BlackZzzverrR [31]

Answer:

A≈196.35cm

Step-by-step explanation:

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4 years ago

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Some help me please i have 9 questions

Lyrx [107]

awnser:

m<3=50

Step-by-step explanation:

seen in the picture if you need help let me know

5 0

3 years ago

A sample of 25 undergraduates reported the following dollar amounts of entertainment expenses last year:

marin [14]

Answer:

$Range = 85$

$\sigma = 28.71$

$Interval = [666.78, 781.62]$

Step-by-step explanation:

Given

The data for 25 undergraduates

Solving (a): Range and Standard deviation

The range is:

$Range = Highest - Least$

From the dataset:

$Highest = 772$

$Least = 687$

So:

$Range = Highest - Least$

$Range = 772-687$

$Range = 85$

The standard deviation is:

$\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n}}$

First, calculate the mean

$\bar x = \frac{769 +691 +............+715}{25}$

$\bar x = \frac{18105}{25}$

$\bar x = 724.2$

So, the standard deviation is:

$\sigma = \sqrt{\frac{(769-724.2)^2 +(691-724.2)^2 +(699-724.2)^2 +(730-724.2)^2 +............+(715-724.2)^2}{25}}$

$\sigma = \sqrt{\frac{20604}{25}}$

$\sigma = \sqrt{824.16}$

$\sigma = 28.71$

Solving (b): The interval of the 95% of the observation.

Using the emperical rule, we have:

$Interval = [\bar x - 2*\sigma, \bar x+ 2*\sigma]$

$Interval = [724.2 - 2*28.71, 724.2 + 2*28.71]$

$Interval = [666.78, 781.62]$

4 0

3 years ago

Value of the underlined of 56

Elodia [21]

Anyway, the value of 5 is 50 and the value of 6 is 6 as in the ones place.

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4 years ago

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