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yawa3891 [41]
3 years ago
13

The random variable X takes on the values of 2, 5, n, and 15. The probability distribution of X is shown in the following table

Mathematics
2 answers:
iVinArrow [24]3 years ago
7 0

Answer:

12

Step-by-step explanation:

I did it on College Board

Marina86 [1]3 years ago
6 0

The question is missing some parts. Here is the complete question.

The random variable X takes on the values of 2, 5, n and 15. The probability distribution of X is shown in the table below.

The expected value of X is 9.1. What is the value of n?

a) 8

b) 8.52

c) 10

d) 12

e) 14.4

Answer: d) 12

Step-by-step explanation: In a probability distribution, <u>Expected</u> <u>Value</u> is the average (or mean) value a distribution can assume.

The Expected Value, E(X), can be determine by:

E(X)=\Sigma xP(x)

in which

x is how many times an event happens

P(x) is the probability of an event happening

The table below n is x and expected value is 9.1, then:

9.1=2*0.1+5*0.4+0.2n+15*0.3

9.1=0.2n+6.7

0.2n=2.4

n = 12

<u>Value of </u><u>n</u><u> in this probability distribution is </u><u>12</u>.

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