Write the equation of a line that passes through the points ( 2 , - 5 ) and ( 8 , - 2 ).
1 answer:
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It's given in the question,
P, Q, V and K are collinear.
VP = 14x + 4
PK = x + 630
VQ = 17x + 6
KQ = 11x + 5
By segment addition postulate,
KQ + VQ + VP = KP
Substitute the values in the expression,
(11x + 5) + (17x + 6) + (14x + 4) = x + 630
(11x + 17x + 14x) + (5 + 6 + 4) = x + 630
42x + 15 = x + 630
42x - x = 630 - 15
41x = 615
x =
x = 15
Therefore, value of VP = (14x + 4)
= 14(15) + 4
= 214 units
Learn more,
Answer:
P'(7, 5)
Step-by-step explanation:
Rule for the transformation of a point defines,
Reflection of a point P(x, y) about a line, x = 1 which is parallel to y-axis.
Line x = 1 works like a mirror so the distance between the line and the image point will be equal to the distance between the line and the original point.
Distance between the line and a point (-1, 5) = 4
Therefore, distance between the line and the image point = 4
Coordinates of the image point will be,
P'(3, 5)
