Answer:
y = 1/5x -3
Step-by-step explanation:
Use y = mx +b as your model. We plug in our slope for me and our y-intercept for b.
Its not clearly given that whether EBF = 2x + 9 or 2x - 9.
I have written the solution for both.
If EBF = 2x + 9,
then ABF = 6x + 26 and ABE = 11x - 31.
Now, ABE = ABF + EBF
11x - 31 = (6x + 26) + (2x + 9)
= (6x + 2x) + (26 + 9)
= 8x + 35
11x - 8x = 35 + 31
3x = 66
x = 22
Therefore, ABF = 6x + 26 = 6(22) + 26 = 132 + 26 = 158°
If EBF = 2x - 9,
then ABF = 6x + 26 and ABE = 11x - 31.
Now, ABE = ABF + EBF
11x - 31 = (6x + 26) + (2x - 9)
= (6x + 2x) + (26 - 9)
= 8x + 17
11x - 8x = 17 + 31
3x = 48
x = 16
Therefore, ABF = 6x + 26 = 6(16) + 26 = 96 + 26 = 122°
Answer:
The ball will hit the ground in 1.33 s if no one touches it. The equation has 2 real solutions.
Step-by-step explanation:
The ball will hit the ground when its height is equal to 0 meters, therefore using this value in the expression and solving for "t" will give us the correct solutions.
The ball will hit the ground in 1.33 s if no one touches it. The equation has 2 real solutions.
Answer:
8 / sqrt(3)
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
tan theta = opp / adj
tan A = BC / AC
tan 30 = BC / 8
8 tan 30 = BC
8 * sqrt(3)/3 = BC
8/3 sqrt(3) = BC
Answer:
A.) The coordinates of M' are (-2/4, -4/5)
The coordinates of N' are (1/5, 1)
B.) The scale factor of the dialation is 3