Question

Find the mean, variance, and standard deviation of the sample with

Answer 1

Mean:-

$\\ \tt\hookrightarrow \dfrac{\sum x}{n}=\dfrac{210}{10}=21$

Standard Deviation:-

$\\ \tt\hookrightarrow \sqrt{\dfrac{\sum x^2}{n}-(\sum x/n)^2}$

$\\ \tt\hookrightarrow \sqrt{\dfrac{5006}{10}-(21)^2}$

$\\ \tt\hookrightarrow \sqrt{500.6-441}$

$\\ \tt\hookrightarrow \sqrt{59.6}$

$\\ \tt\hookrightarrow 7.72$

Variance:-

$\\ \tt\hookrightarrow (S. D)^2=(7.72)^2=59.6$