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3 years ago

Name the line and plane shown in the figure.

Mathematics

1 answer:

ira [324]3 years ago

7 0

Answer: I think your answer is B, but I'm not positive

Step-by-step explanation:

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What is 5 1/6 minus 1 1/3

zaharov [31]

We must find the common denominator.

LCM(6, 3) = 6

$5\dfrac{1}{6}-1\dfrac{1}{3}=5\dfrac{1}{6}-1\dfrac{1\cdot2}{3\cdot2}=5\dfrac{1}{6}-1\dfrac{2}{6}=(5-1)+\left(\dfrac{1}{6}-\dfrac{2}{6}\right)=4-\dfrac{1}{6}=3\dfrac{5}{6}$

or other method of calculating the difference

$5\dfrac{1}{6}-1\dfrac{2}{6}=4\dfrac{6+1}{6}-1\dfrac{2}{6}=4\dfrac{7}{6}-1\dfrac{2}{6}=(4-1)+\left(\dfrac{7}{6}-\dfrac{2}{6}\right)=3\dfrac{5}{6}$

7 0

3 years ago

An object is launched from a launching pad 208 ft. above the ground at a velocity of 192ft/sec. what is the maximum height reach

Alexeev081 [22]

Answer:

h(x) = -16x² + 192x + 208

784ft

6 sec

13 sec

Step-by-step explanation:

h(x) = -16x² +vx + h $_{o}$

here v represent velocity

$h_{o}$ represent initial height of launch

h(x) = -16x² + 192x + 208

here a = -16

b = 192

c = 208

x = -b/2a

= -192/2(-16)

= 6

plug this value in the equation

h(x) = -16(6)² + 192(6) + 208

= 784ft

Plug h(x)=0 in the equation

0 = -16x² + 192x + 208

divide equation by -16

x² - 12x - 13 = 0

Factors

1x * -13x = -13

1x - 13x = -12

Factorised form

x² - 12x - 13 = 0

x² + x - 13x - 13 = 0

x(x+1) -13(x+1) = 0

(x+1)(x-13) = 0

x = -1

x = 13

Since time can not be negative so we will reject x = -1

3 0

3 years ago

What is 2 7/8 plus 2 3/8 ?

enot [183]

2 7/8 + 2 3/8= 4 10/8, which equals 5 2/8, which is also equal to 5 1/4

8 0

3 years ago

Read 2 more answers

Solve the equations<br>Y=2x-4, 3x+y=1

liberstina [14]

Step-by-step explanation:

$y = 2x - 4$

$3x + y = 1$

$y = 1 - 3x$

Equating,

$2x - 4 = 1 - 3x$

$2x + 3x = 1 + 4$

$5x = 5$

$x = 1$

Placing it,

$y = 1 - 3( 1)$

$y = 1 - 3$

$y = - 2$

6 0

3 years ago

PLZ ans have mocks plz

Yanka [14]

Answer:

The table will be:

x |-2 | -1 | 0 | 1 | 2

y | 1 | 4 | 5 | 4 | 2

Step-by-step explanation:

The function is:

$y=5-x^{2}$

a) The x values of the table is:

x |-2 | -1 | 0 | 1 | 2

So, when x = -2, y will be:

$y(-2)=5-(-2)^{2}=5-4=1$

Doing the same with the other x values we have:

$y(-1)=5-(-1)^{2}=5-1=4$

$y(0)=5-(0)^{2}=5$

$y(1)=5-(1)^{2}=5-1=4$

$y(2)=5-(2)^{2}=5-4=1$

The table will be:

x |-2 | -1 | 0 | 1 | 2

y | 1 | 4 | 5 | 4 | 1

I hope it helps you!

5 0

3 years ago