Answer:
Hi! The answer to your question is x = 7
Step-by-step explanation:
☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆
☆Brainliest is greatly appreciated!☆
Hope this helps!!
- Brooklynn Deka
Answer:
The information we need is that the angle between the sides (that is, angle TVU for triangle TVU and angle WVX for triangle WVX) need to be equal.
These angles are vertically opposite angles, because they are formed by two lines crossing, so these angles are equal.
Step-by-step explanation:
The SAS Congruence Theorem says that if two triangles have 2 equal sides and the angle between these sides are also equal, the triangles are congruent.
In this question, we know that the sides UV and VW are congruent, as V is the midpoint of UW. We also know that TV = VX, so now we have two equal sides for each triangle.
The information we need is that the angle between the sides (that is, angle TVU for triangle TVU and angle WVX for triangle WVX) need to be equal.
These angles are vertically opposite angles, because they are formed by two lines crossing, so these angles are equal.
Now we can conclude that the triangles are congruent.
X+3y=7
x-3y=1
add them together
x+3y=7
<u>x-3y=1 +
</u>2x+0y=8
2x=8
divide 2
x=4
subsitute
x+3y=7
4+3y=7
subtract 4
3y=3
divid 3
y=1
x=4
y=1
answer is A
<u />
Answer:
Because the sectors are of equal size, each sector has the same probability of happening.
So for every number, you have a probability of 0.2 of it appearing.
Because you have three odd numbers, the probability to land on an odd number on each spin is 0.6. You can also say that the probability to not have an odd number is 0.4.
So what is the probability to have 0 odd number in two spins?
What is the probability to have 1 odd number in two spins? You can have one odd number on the first or one odd on the second spin, that is why we add the probabilities.
What is the probability to have 2 odd numbers in two spins?
To verify if we did a good job, we add all the probabilities. We should get 1.
.
So to slide your bars, you slide them up to the number I gave you for each case.
Hope this helps!
