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4 years ago

Y=3x+5 and y=3x-10

1 answer:

7 0

Okay..,
actually there is some mistake in the problem..!!

as only the content term is changed for both the equation while X and Y are same..

please provide correct question

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How do I solve the inequality for this: 10 < 9 + x

Firlakuza [10]

Subtract 9 from each side of the equation. so you would get 1<x. meaning that any number larger then 1 would correctly solve the equation.

4 0

3 years ago

Read 2 more answers

Could someone please help me with this?

allsm [11]

Answer:

21.5 mm^2

Step-by-step explanation:

First find the area of the square

A = s^2 = 10^2 =100

Then find the area of the circle

d = 10 so r = d/2 = 10/2 =5

A = pi r^2

A = 3.14 (5)^2 =78.5

The difference is the shaded region

100-78.5 =21.5

7 0

3 years ago

Read 2 more answers

I need help brainliest!!!

ratelena [41]

Answer:

First one: function and linear

Second one: function and non-linear

Third one: not a function and linear

Step-by-step explanation:

• The first one is set in the linear function formula y=mx+b, so it is a linear function.

• The second one is a non-linear because functions with exponents have different shapes and can intersect more than once unline linear functions.

• The third one isn't a function but it is linear because it isn't set equal to a variable and it would become a linear if you simply it to isolate a variable.

I hope this helps!!!

5 0

3 years ago

How do you solve for sides a and b of a triangle when you know the value of c?

sasho [114]

Assuming you have some angle measures, you could use the Law of Sines to solve for the missing side lengths, which states that,
$\frac{a}{sinA}= \frac{b}{sinB}= \frac{c}{sinC}$ ,
where a, b, and c correspond to the given sides you have, and A, B, and C represent the angles you have.

In this scenario, you would have to have the values for c (which we do), and have the angle measure of C. In addition, we would also need an angle measure that is either A or B.

Hope this helps a bit!

:)

7 0

3 years ago

B-3a=2 3B- 6a=12 solve algebraicly show steps

lora16 [44]

B - 3A = 2
3B - 6A = 12

(2)B - (6)A =4
3B - 6A = 12

Subtract

-B = -8
B = 8

Plugin 8 for B

8 - 3A = 2
8 = 3A + 2
6 = 3A
2 = A

(Double checking)
3(8) - 6A = 12
-6A = 12-24 = -12
- 6A = -12
Divide by -6
A= 2
It works

A = 2. B = 8. Hope this helps

3 0

3 years ago