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REY [17]
2 years ago
15

Please someone help me. I need to bring my grade up... please :(

Mathematics
1 answer:
Simora [160]2 years ago
4 0

Answer:

give me about 10 mins I can give you the answer

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A high school track coach wanted to test whether giving the students an energy drink could affect performance during the 100 met
kondaur [170]

The inference that can be made about the results is that; energy drinks enhances performance during 100 meters race.

<h3>How to find inference from a given data?</h3>

From the given table and histogram, we can see that;

Group 1 average race time = 10.8

Group 2 average race time = 11.6

Thus, since group 1 drank energy drink and had faster times than group 2 without energy drinks, the inference that can be made about the results is that energy drinks has enhancing performance during 100 meters race.

Read more about Inference at; brainly.com/question/1611703

#SPJ1

4 0
2 years ago
Find the 21st term of the arithmetic sequence with a first term
larisa86 [58]
At this case it could be calculated like this: 7+5*20=107
7 0
3 years ago
Simplify (3a-2b)²-2(3a-2b)(a+2b)+(a+2)²​
Mnenie [13.5K]

Answer: 4a2-20ab+12b2+4a+4

the 2 is squareing 4a and 12b

Step-by-step explanation:

expand move the parentheses

multiply the parentheses

collect like terms

6 0
3 years ago
Read 2 more answers
Which system of equations does this graph represent?
jeyben [28]

Answer:

1

Step-by-step explanation:

First, we can find the equation of the parabola. The standard form of a parabola is ax^2 + bx + c,

where c is the y-intercept. The y-intercept on the graph is -5, and every option starts with x^2, so the equation must be x^2 - 5. This rules out options 3 and 4.

Next, we can find the equation of the line. The options are all given in slope-intercept form: y = mx + b, where b is the y-intercept. The y-intercept on the graph is 1, and option 1 has 1 in the place of b. Therefore, option 1 is the answer.

7 0
2 years ago
out of some students appeared in an examination 80% passed in mathematics 75% passed in english and 5% failed in both subjects i
Advocard [28]

Answer:

5000 students appeared in the examination.

Step-by-step explanation:

We solve this question using Venn probabilities.

I am going to say that:

Event A: Passed in Mathematics

Event B: Passed in English.

5% failed in both subjects

This means that 100 - 5 = 95% pass in at least one, which means that P(A \cup B) = 0.95

80% passed in mathematics 75% passed in english

This means that P(A) = 0.8, P(B) = 0.75

Proportion who passed in both:

P(A \cap B) = P(A) + P(B) - P(A \cup B)

Considering the values we have for this problem

P(A \cap B) = P(A) + P(B) - P(A \cup B) = 0.8 + 0.75 - 0.95 = 0.6

3000 of them were passed both subjects how many students appeared in the examination?

3000 is 60% of the total t. So

0.6t = 3000

t = \frac{3000}{0.6}

t = 5000

5000 students appeared in the examination.

4 0
2 years ago
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