What’s does 2 1/5 round to

What is one light year in seconds need it to written out in the conversion format

ra1l [238]

In one year there are 365 days of 24 hours. Each hour has 60 minutes and each minute is 60 seconds long. So, 60s/min x 60 min/hr x 24hr/day x 365 days equals 31,536,000s.

Hope this helps you with your answer. If it is incorrect, then I am sorry.

8 0

4 years ago

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Question 28

alexandr402 [8]

Answer:

Given Rate of interest is r=8%=0.08

Principal Amount is A=5,000

Time is t years

Interest is compounded yearly twice ⟹n=2

Amount =P(1+

n

r

)

nt

=5000×(1+

2

0.08

)

2t

=5,408

(1.0816)

t

=

5000

5408

⟹t=1

7 0

3 years ago

Express 8% as a decimal

konstantin123 [22]

Answer:

0.08

Step-by-step explanation:

5 0

3 years ago

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The volumes of two bodies are measured to be

valentinak56 [21]

Answer:

Sum of volumes = (16.6 ± 0.03) cm³

Difference of volumes = (3.8 ± 0.03) cm³

Step-by-step explanation:

Solution

V₁ = (10.2 ± 0.02) cm³ and V₂ = (6.4 ± 0.01) cm³.

∆V = ± (∆V₁ + ∆V₂)

= ± (0.02 + 0.01) cm³

= ± 0.03 cm³

V₁ + V₂ = (10.2 + 6.4) cm³ = 16.6 cm³ and

V₁ - V₂ = (10.2 - 6.4) cm³ = 3.8 cm³

Hence, sum of volumes = (16.6 ± 0.03) cm³

and difference of volumes = (3.8 ± 0.03) cm³

-TheUnknownScientist

5 0

3 years ago

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After a college football team once again lost a game to their archrival, the alumni association conducted a survey to see if alu

valentina_108 [34]

Answer:

P-value for this hypothesis test is 0.00175.

Step-by-step explanation:

We are given that the alumni association conducted a survey to see if alumni were in favor of firing the coach.

A simple random sample of 100 alumni from the population of all living alumni was taken. Sixty-four of the alumni in the sample were in favor of firing the coach.

Let p = proportion of all living alumni who favored firing the coach

SO, Null Hypothesis, $H_0$ : p = 0.50 {means that the majority of alumni are not in favor of firing the coach}

Alternate Hypothesis, $H_A$ : p > 0.50 {means that the majority of alumni are in favor of firing the coach}

The test statistics that will be used here is One-sample z proportion statistics;

T.S. = $\frac{\hat p-p}{{\sqrt{\frac{\hat p(1-\hat p)}{n} } } } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of the alumni in the sample who were in favor of firing the coach = $\frac{64}{100}$ = 0.64

n = sample of alumni = 100

So, test statistics = $\frac{0.64-0.50}{{\sqrt{\frac{0.64(1-0.64)}{100} } } } }$

= 2.92

Now, P-value of the hypothesis test is given by ;

P-value = P(Z > 2.92) = 1 - P(Z $\leq$ 2.92)

= 1 - 0.99825 = 0.00175

Therefore, the P-value for this hypothesis test is 0.00175.

4 0

4 years ago