I'm sorry but I don't see any questions?
Answer:
for quadratic equation 1
y^2-10y+21=0
Step-by-step explanation:
y^2-7y-3y+21=0
y(y-7)-3(y-7)=0
(y-7)(y-3)=0
y-7=0,y-3=0
y=7,y=3
y=(3,7)
for quadratic equation 2
16p^2-8p+1=0
16p^2-4p-4p+1=0
4p(4p-1)-1(4p-1)=0
(4p-1)twice=0
4p-1=0,4p-1=0
4p=1
p=1/4 twice
for quadratic equation 3
x^2-400=0
x^2=400
x=√400
x=20
for quadratic equation 4
-16m^2-8m-1=0
multiply the equation by -
16m^2+8m+1=0
16m^2+4m+4m+1=0
4m(4m+1)1(4m+1)=0
4m+1=0 twice
m=-1/4 twice
for quadratic equation 5
-3n^2+75=0
divide both side by -3
-3n^2/-3=-75/-3
n^2=25
n=√25
n=5
If it take some x minutes to upload some y digital photographs, it means it has an average of: x/y minutes to upload a single digital photograph. Then, to upload z photographs, you just multiply x/y by z.
Spoilers for answer:
If it take 7.2 minutes to upload 8 digital photographs, it means it has an average of: 7.2/8 = 0.9 minutes to upload a single digital photograph. This means that, by this rate, it will take 20 * 0.9 = 18 minutes to upload 20 photographs to the website.
The scale factor applied to the model is 8000. 8000 times one equals 8000
Answer:
P = 2(n - 6) + 2(n^2 - 8)
Step-by-step explanation:
Remembering that Area = Length times Width, we factor the given function
A = n^3 - 6n^2 - 8n + 48 in the expectation that the resulting factors represent the length and width respectively:
A = n^3 - 6n^2 - 8n + 48 factors as follows:
A = n^2(n - 6) - 8(n - 6), or A = (n - 6)(n^2 - 8)
We can label '(n - 6)' "width" and '(n^2 - 8'
length.
Then the perimeter, P, of the rectangle is P = 2(length) + 2(width). which works out here to:
P = 2(n - 6) + 2(n^2 - 8)
