No because if you divide 1.25 by two to find out what the half is in 2.5, it would be .62… and since she wants to buy 2.5 pounds, you've already figured out the .5, so 1.25x2 + .62, it would be 3.12.
Illusion103

3 0

3 years ago

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Find the length of diagonal HJ. Round to the nearest hundredth.

Alisiya [41]

Answer:

The length of the diagonal HJ is 10.82 units

Step-by-step explanation:

* Lets revise the rule of the distance between two points

- $d=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$ , where

$(x_{1},y_{1})$ and $(x_{2},y_{2})$ are the two points

* Lets use this rule to find the length of the diagonal HJ

∵ The coordinates of point H are (-4 , 3)

∵ The coordinates of point J are (5 , -3)

∴ $x_{1}=-4$ and $x_{2}=5$

∴ $y_{1}=3$ and $y_{2}=-3$

- Lets find the length of the diagonal HJ by using the rule above

∴ HJ = $\sqrt{(5-(-4))^{2}+(-3-3)^{2}}=\sqrt{(5+4)^{2}+(-6)^{2}}$

∴ HJ = $\sqrt{(9)^{2}+36}=\sqrt{81+36}=\sqrt{117}=10.81665$

∴ HJ = 10.82

* The length of the diagonal HJ is 10.82 units

7 0

3 years ago