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4 years ago

Which expression is represented on the number line?

Mathematics

1 answer:

stealth61 [152]4 years ago

3 0

the answer is C. 2(-3)

-you're going down by 3 two times, which is basically 2(-3) = -6. you land on -6, so it is the right answer.

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4d+q=14.95. Find d and q.

goldenfox [79]

Answer:

I love algebra anyways

The ans is in the picture with the steps how i got it

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Step-by-step explanation:

6 0

3 years ago

What is is 3/4 equal too

Paladinen [302]

3/4=0.75
0.75 would be equal to 3/4

6 0

4 years ago

Read 2 more answers

I need this math problem done as soon as possible!

Vesna [10]

Answer:

See below

Step-by-step explanation:

Parent function:

y = 3ˣ

Transformed function:

y = 4(3)⁻²ˣ⁺⁸ + 6, (note. I see this as 8, sorry if different but it doesn't make any change to transformation method)

Transformations to be applied:

f(x) → f(-x) reflection over y-axis
f(-x) → f(-2x) stretch horizontally by a factor of 2
f(-2x) → f(-2x + 8) translate 8 units right
f(-2x + 8) → 4f(-2x + 8) stretch vertically by a factor of 4
4f(-2x + 8) → 4f(-2x + 8) + 6 translate 6 units up

7 0

3 years ago

Initially, there are 40 grams of A and 50 grams of B, and for each gram of B, 2 grams of A is used. It is observed that 15 grams

hram777 [196]

Answer:

$X(16)=25.71grams$

Step-by-step explanation:

let $X(t)$ denote grams of $C$ formed in $t$ mins.

For $X grams$ of $C$ we have:

$\frac{2}{3}Xg$ of A and $\frac{1}{3}Xg$ of B

Amounts of A,B remaining at any given time is expressed as:

$40-\frac{2}{3}Xg$ of A and $50-\frac{1}{3}Xg$ of B

Rate at which C is formed satisfies:

$\frac{dX}{dt} \infty(40-\frac{2}{3}X)(50-\frac{1}{3}X)->\frac{dX}{dt}=k(90-X)\\\therefore \frac{dX}{(90-X)^2}=kdt->\int{\frac{dX}{(90-X)^2}} \, =\int {k} \, dt \\\therefore \frac{1}{90-X}=kt+c->90-X=\frac{1}{kt+c}\\\\X(t)=90-\frac{1}{kt+c}$

Apply the initial condition, $X(0)=0$ ,to the expression above

$0=90-\frac{1}{c} \ \ ->c=\frac{1}{90}\\\therefore\\X(t)=90-\frac{1}{kt+\frac{1}{90}} \ \ ->X(t)=90-\frac{90}{90kt+c}$

Now at $X(8)=15$ :

$15=90-\frac{90}{90\times 8k+1} \ ->75=\frac{90}{720k+1}\\k=0.0002778$

Substitute in X(t) to get

$X(t)=90-\frac{90}{0.0002778t\times 90+1}\\X(t)=90-\frac{90}{0.25t+1}\\But \ t=16\\\therefore X(t)=90-\frac{90}{0.025\times16+1}\\X(t)=25.71$

5 0

3 years ago

QUESTION Diego measured the length of a pen to be 22 cm. The actual length of the pen is 23 cm.

STALIN [3.7K]

4.3 bc it’s right and i did the assignment

5 0

3 years ago