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3 years ago

8

QUESTION Diego measured the length of a pen to be 22 cm. The actual length of the pen is 23 cm.

1 answer:

STALIN [3.7K]3 years ago

5 0

4.3 bc it’s right and i did the assignment

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The AAA system contains 3 independent components in parallel, each with probability of failure 0.4. Find the expected number of

Gre4nikov [31]

Answer:

Step-by-step explanation:

For each component, there are only two possible outcomes. Either it fails, or it does not. The components are independent. We want to know how many outcomes until r failures. The expected value is given by

$E = \frac{r}{p}$

In which r is the number of failures we want and p is the probability of a failure.

In this problem, we have that:

r = 1 because we want the first failed unit.

$p = 0.4[\tex]So[tex]E = \frac{r}{p} = \frac{1}{0.4} = 2.5$

The expected number of systems inspected until the first failed unit is 2.5

8 0

3 years ago

Find an equation of the tangent to the curve x =5+lnt, y=t2+5 at the point (5,6) by both eliminating the parameter and without e

svet-max [94.6K]

ANSWER

$y = 2x -4$

EXPLANATION

Part a)

Eliminating the parameter:

The parametric equation is

$x = 5 + ln(t)$

$y = {t}^{2} + 5$

From the first equation we make t the subject to get;

$x - 5 = ln(t)$

$t = {e}^{x - 5}$

We put it into the second equation.

$y = { ({e}^{x - 5}) }^{2} + 5$

$y = { ({e}^{2(x - 5)}) } + 5$

We differentiate to get;

$\frac{dy}{dx} = 2 {e}^{2(x - 5)}$

At x=5,

$\frac{dy}{dx} = 2 {e}^{2(5 - 5)}$

$\frac{dy}{dx} = 2 {e}^{0} = 2$

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

$y-y_1=m(x-x_1)$

$y - 6 = 2(x - 5)$

$y = 2x - 10 + 6$

$y = 2x -4$

Without eliminating the parameter,

$\frac{dy}{dx} = \frac{ \frac{dy}{dt} }{ \frac{dx}{dt} }$

$\frac{dy}{dx} = \frac{ 2t}{ \frac{1}{t} }$

$\frac{dy}{dx} = 2 {t}^{2}$

At x=5,

$5 = 5 + ln(t)$

$ln(t) = 0$

$t = {e}^{0} = 1$

This implies that,

$\frac{dy}{dx} = 2 {(1)}^{2} = 2$

The slope of the tangent is 2.

The equation of the tangent through

(5,6) is given by

$y-y_1=m(x-x_1)$

$y - 6 = 2(x - 5) =$

$y = 2x -4$

5 0

3 years ago

Hello I was wondering if someone would help me with this tricky question?

Rudiy27

Answer:

The two coordinates should be (6, 3) and (10, 4).

Step-by-step explanation:

rise / run

y-value of the 2nd coordinate = 3 + 1 = 4

x-value of the 2nd coordinate = 6 + 4 = 10

The two coordinates should be <u>(6, 3) and (10, 4)</u>.

7 0

3 years ago

Pamela ran 7/10 mile on Tuesday and 3/8 mile on Thursday. How much fatter did she run on Tuesday ?

Len [333]

Answer:

$Difference = \frac{13}{40}$

Step-by-step explanation:

Given

$Thursday = \frac{3}{8}\ mile$

$Tuesday = \frac{7}{10}\ mile$

Required

How much farther is she on Tuesday

To do this, we simply calculate the difference between distance covered on both days.

$Difference = Tuesday-Thursday$

$Difference = \frac{7}{10} - \frac{3}{8}$

Take LCM

$Difference = \frac{28- 15}{40}$

$Difference = \frac{13}{40}$

<em>Hence, she ran 13/40 mile farther on Tuesday</em>

3 0

3 years ago

Solve using method of your choice. PLease help 28 points

Burka [1]

$7x+y=-20\\
x-3y=-50\\\\
21x+3y=-60\\
\underline{x-3y=-50}\\
22x=-110\\
x=-5\\\\
-5-3y=-50\\
3y=45\\
y=15
$

-----------------------------------------------------

$(5x-8y)^2=-25$
No solution in real numbers.

5 0

3 years ago