Answer:
A. 
B. 
C. 
Step-by-step explanation:
A.
. Any number could work as long as the coefficients for x and y stays the same. You are basically imposing that the quantity 2x-4y (if you bring 4y to the LHS) is equal to both -3 AND
, or any number you like. But yesterday was 3/14 so let's pick a fun number!
B.
Or
. Or as long as you don't pick the same ratios of x and y you're golden. But x=1 is the easiest that comes to mind
C.
. To get infinitely many solutions you just have to rewrite the equation again. Maybe move things around if you prefer, or multiply everything by a number you lile.
Answer:
441/4
Step-by-step explanation:
Find the GCD of numerator and denominator
GCD of 1323 and 12 is 3
Divide both the numerator and denominator by the GCD
1323 ÷ 3
12 ÷ 3
Reduced fraction:
441/4
________
Hope this helps!
-Lexi
Answer:
1
Step-by-step explanation:
Answer:
Th correct option is D. 13
Therefore the value of x is 13.
Step-by-step explanation:
Given:
measure of an intercepted arc = 86°
Center Angle = 86°
measure of the inscribed angle creating the intercepted arc= (3x+4)°
Angle Inscribed in arc = (3x+4)°
To Find:
value of x = ?
Solution:
Inscribed Angle Theorem:
The inscribed angle theorem states that an angle θ inscribed in a circle is half of the central angle 2θ that subtends the same arc on the circle.

Substituting the values we get

Therefore the value of x is 13.
Hello Bubbleshi !
The first step you need to do is get everything in like terms.
- 1/6 and - 7 /4
Look at the denominator (number on the bottom)
6 and 4 go into 12, so lets check that out.
-1/6 , how can we get 12 from the denominator? Multiply it by 2.
So you multiply both the numerator (number on the top) and the denominator.
-1/6 becomes -2/12.
With -7/4, you want to get the 4 as a 12 (like terms!) so once again you multiply it by 3, and multiply the numerator as well.
-7/4 becomes -21/12.
-2/12 + (-21/12) is your final form of the problem.
You add -2 and -21 in the numerator, which is -23.
So its -23/12 which is your final answer.
Let me know if you need any more help!