Given the equation 2x = 4y - 3 write another linear equation that would create a system that has the number of solutions listed
1 answer:
Answer:
A.
B.
C.
Step-by-step explanation:
A. . Any number could work as long as the coefficients for x and y stays the same. You are basically imposing that the quantity 2x-4y (if you bring 4y to the LHS) is equal to both -3 AND
, or any number you like. But yesterday was 3/14 so let's pick a fun number!
B. Or
. Or as long as you don't pick the same ratios of x and y you're golden. But x=1 is the easiest that comes to mind
C. . To get infinitely many solutions you just have to rewrite the equation again. Maybe move things around if you prefer, or multiply everything by a number you lile.
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The first thing you should observe in the graph is that
6x + 4y = 24 is a line with a negative slope.
2x-4y = -8 is a line with positive slope.
After you identify the functions you can choose the correct affirmations.
The x-coordinate of the solution is 2.
The y-coordinate of the solution is 3.
The ordered pair that is the solution to the system lies in Quadrant I.
6x + 4y = 24 is a line with a negative slope.
2x-4y = -8 is a line with positive slope.
After you identify the functions you can choose the correct affirmations.
The x-coordinate of the solution is 2.
The y-coordinate of the solution is 3.
The ordered pair that is the solution to the system lies in Quadrant I.