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Lilit [14]
2 years ago
9

Given the equation 2x = 4y - 3 write another linear equation that would create a system that has the number of solutions listed

Mathematics
1 answer:
Harman [31]2 years ago
7 0

Answer:

A. 2x-4y=\pi
B.  x=1

C. 2x-4y=3

Step-by-step explanation:

A. 2x-4y=\pi. Any number could work as long as the coefficients for x and y stays the same. You are basically imposing that the quantity 2x-4y (if you bring 4y to the LHS) is equal to both -3 AND \pi, or any number you like. But yesterday was 3/14 so let's pick a fun number!

B.  x=1 Or y=1. Or as long as you don't pick the same ratios of x and y you're golden. But x=1 is the easiest that comes to mind

C. 2x-4y=3. To get infinitely many solutions you just have to rewrite the equation again. Maybe move things around if you prefer, or multiply everything by a number you lile.

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Answer: 14/25 = 56/100

               11/20 =  55/100

               14/25 > 11/20

Step-by-step explanation:

The least common multiple of 20 and 25 is 100.

(100 = 20*5, 25*4)

So we can take the common denominator 100.

14*4/25*4 =56/100. ∴14/25 = 56/100

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56>55

∴56/100 > 55/100

∴14/25 > 11/20

Hope it's good;)

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Answer:

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Step-by-step explanation:

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