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2 years ago

The sum of two numbers is 63. The larger number is 23 more than the smaller number. What are the numbers?

Mathematics

2 answers:

Sunny_sXe [5.5K]2 years ago

5 0

x+y=63

x=y+23

y+23+y =63

2y +23 = 63

2y =40

y=40/2 =20

y = 20

x = 20+23=43

the numbers are 20 & 43

Y_Kistochka [10]2 years ago

3 0

The numbers are 20 and 43

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Answer:

B and C

Step-by-step explanation:

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2 years ago

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2 years ago

I need help with this and please show your work

Nikolay [14]

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3 years ago

Solve for x<br> (1/x) -2/3 = (4x)

Vadim26 [7]

The value of x is $x=\frac{-1+\sqrt{37}}{12}$ and $x=\frac{-1-\sqrt{37}}{12}$

Step-by-step explanation:

The equation is $\frac{1}{x}-\frac{2}{3}=4 x$

Subtracting by $4x$ on both sides,

$\frac{1}{x}-\frac{2}{3}-4 x=0$

Taking LCM,

$\frac{3-12 x^{2}-2 x}{3 x}=0$

Multiplying by 3x on both sides,

$-12 x^{2}-2 x+3=0$

Dividing by (-) on both sides,

$12 x^{2}+2 x-3=0$

Using quadratic formula, we can solve for x.

$\begin{aligned}x &=\frac{-2 \pm \sqrt{2^{2}-4 \cdot 12 \cdot(-3)}}{2 \cdot 12} \\&=\frac{-2 \pm \sqrt{4+144}}{2 \cdot 144} \\&=\frac{-2 \pm \sqrt{148}}{24} \\&=\frac{-2 \pm 2 \sqrt{37}}{24}\end{aligned}$