Answer:
third option
Step-by-step explanation:
Given
3 ![\left[\begin{array}{ccc}-2&5\\1&0\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-2%265%5C%5C1%260%5C%5C%5Cend%7Barray%7D%5Cright%5D)
Multiply each element in the matrix by 3
= ![\left[\begin{array}{ccc}3(-2)&3(5)\\3(1)&3(0)\\\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D3%28-2%29%263%285%29%5C%5C3%281%29%263%280%29%5C%5C%5Cend%7Barray%7D%5Cright%5D)
=
The launchers height above the ground at zero distance h(x)+0+0+.4= 4 meaning that the height is 4 <span />
Answer:
They are similar because both triangles are the same. Triangle ABC is just smaller than triangle ADE.
Answer:
First option: 
Step-by-step explanation:


Multiply both sides by y:






