I think true, unless there is a loop hole.
I don’t know what you want an answer for but…:
when x=0, y=-5
when y=0, x=15/2
when x=1, y=-13/3
x=(3(y+5))/2
<span>f(x) =-(x+9)(x-21)
Manipulating algebrically,
We get,
</span>f(x) =-(x+9)(x-21)
= -(x^2 -21x + 9x - 189)
= -(x^2 -12x - 189)
= -x^2 + 12x + 189
Axis of symmetry = -b/2a
plugging the values,
x = -12/-2
= 6
The bottom square portion would be 10 x 10 = 100 square inches.
The area of the triangle would be 1/2 x base x height.
The base is 10 - 6 = 4 inches.
The height is 16 -10 = 6 inches.
Area = 1/2 x 4 x 6 = 12 square inches.
Total area = 100 + 12 = 112 square inches.
Answer:
θ = 5π/6 rad and 11π/6 rad
Step-by-step explanation:
Given the expression cotθ+√3=0
Subtract √3 from both sides
cotθ+√3-√3=0-√3
cotθ = -√3
Since cotθ = 1/tanθ
1/tanθ = -√3
Reciprocate both sides:
tanθ = -1/√3
θ = tan^-1(-1/√3)
θ = -30°
Since the angle is negative, and tanθ is negative in the second and fourth quadrant.
In the second quadrant;
θ = 180-30
θ = 150°
Since 180° = πrad
150° = 150π/180
150° = 5π/6 rad
In the fourth quadrant;
θ = 360-30
θ = 330°
Since 180° = πrad
330° = 330π/180
330° = 11π/6 rad
Hence the solutions are 5π/6 rad and 11π/6 rad.