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Lisa [10]
3 years ago
7

according to the fundamental theorem of algebra , how many zeros does the polynomial below have x^4 +5x^3+10x^2+20x+24

Mathematics
2 answers:
Vinil7 [7]3 years ago
8 0

Answer:

4

Step-by-step explanation:

the Fundamental Theorem of Algebra states that for any polynomial of degree n, there are n roots, some of which may be complex

The polynomial shown is of degree 4 ( highest exponent of x )

Hence the polynomial has 4 roots/ zeros



laiz [17]3 years ago
5 0

Answer:

4

Step-by-step explanation:

Cause the highest power is 4

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k:6x-14y=-28\ \ \ \ |subtract\ 6x\ from\ both\ sides\\\\-14y=-6x-28\ \ \ \ \ \ |divide\ both\ sides\ by\ (-14)\\\\y=\frac{-6}{-14}x-\frac{28}{-14}\\\\y=\frac{3}{7}x+2\\----------------------------\\l:3y-7x=-14\ \ \ \ \ |add\ 7x\ to\ both\ sides\\\\3y=7x-14\ \ \ \ \ \ |divide\ both\ sides\ by\ 3\\\\y=\frac{7}{3}x-\frac{14}{3}

Two\ lines\ are\ perpendicular\ if\ product\ of\ the\ slopes\ is\ equal\ -1.\\\\k:y=\frac{3}{7}x+2\to the\ skolpe\ m_k=\frac{3}{7}\\\\l:y=\frac{7}{3}x-\frac{14}{3}\to the\ slope\ m_l=\frac{7}{3}\\\\m_k\times m_l=\frac{3}{7}\times\frac{7}{3}=1\neq-1\\\\conclusion:the\ lines\ are\ not\ perpendicular\\\\Two\ lines\ are\ parallel\ if\ the\ slopes\ are\ equal.\\\\m_k=\frac{3}{7};\ m_l=\frac{7}{3}\to m_k\neq m_l\\\\conclusion:the\ lines\ are\ not\ parallel


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3 0
3 years ago
Read 2 more answers
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kipiarov [429]
\frac{5x^{5}-3x^{3}+2x^{2}-x}{x+2}=5x^{4}-10x^{3}+17x^{2}-32x+63- \frac{126}{x+2}

The coefficient of the x term is -32.
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3 years ago
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Answer:

8/5 or 1.6

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Rise over run.

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