The limit from 1 to 2 of the given antiderivative is; -0.19865
<h3>What is the Limit of the Integral?</h3>
We are given the antiderivative of f(x) as sin(1/(x² + 1)). Thus, to find the limit from 1 to 2, we will solve as;
⇒ (sin ¹/₅) - (sin ¹/₂)
⇒ 0.19866 - 0.47942
⇒ -0.19865
Complete Question is;
If sin(1/(x² + 1)) is an anti derivative for f(x), then what is the limit of f(x)dx from 1 to 2?
Read more about integral limits at; brainly.com/question/10268976
the answer is b i believe
Answer:
C
It's C because the explanation of the description connects with the text.
The Treaty of Paris.. I think that would be the answer.
The reaction quotient can be obtained from the initial concentration while the equilibrium constant can only be obtained from the concentrations at equilibrium.
<h3>What is reaction quotient?</h3>
The term reaction quotient refers to the amount of reactants and products that are present in the system at a particular time. Given a reaction;
H2(g) + I2(g) ⇄ 2HI
Qc = [HI]^2[H2] [I2]
The question is incomplete as the other details are not clear. However, It is important to note that reaction quotient can be obtained from the initial concentration while the equilibrium constant can only be obtained from the concentrations at equilibrium.
Learn more about reaction quotient: brainly.com/question/8205004?