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Mamont248 [21]
3 years ago
9

3 ordered pairs that satisfy the equation y=12x

Mathematics
2 answers:
Nataly_w [17]3 years ago
6 0
(1, 12)
(2, 24)
(3, 36)
OLga [1]3 years ago
5 0
(0, 0), (1, 12), (2, 24)
x= 0 y=12*0 y=0
x=1 y=12*1 y=12
x=2 y=12*2 y=24
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PLEASE HELP<br><br>divide. (3x-2)(x-4)-(x-4)(6-5x)<br>/(4-x)(8x-1)​
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Answer:

x = 39/74 - sqrt(1817)/74 or x = 39/74 + sqrt(1817)/74

Step-by-step explanation:

Solve for x:

(x - 4) (3 x - 2) - ((6 - 5 x) (x - 4) (8 x - 1))/(4 - x) = 0

Simplify and substitute y = 4 - x.

(x - 4) (3 x - 2) - ((6 - 5 x) (x - 4) (8 x - 1))/(4 - x) = -434 + 257 (4 - x) - 37 (4 - x)^2

= -37 y^2 + 257 y - 434:

-37 y^2 + 257 y - 434 = 0

Divide both sides by -37:

y^2 - (257 y)/37 + 434/37 = 0

Subtract 434/37 from both sides:

y^2 - (257 y)/37 = -434/37

Add 66049/5476 to both sides:

y^2 - (257 y)/37 + 66049/5476 = 1817/5476

Write the left hand side as a square:

(y - 257/74)^2 = 1817/5476

Take the square root of both sides:

y - 257/74 = sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Add 257/74 to both sides:

y = 257/74 + sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Substitute back for y = 4 - x:

4 - x = 257/74 + sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Subtract 4 from both sides:

-x = sqrt(1817)/74 - 39/74 or y - 257/74 = -sqrt(1817)/74

Multiply both sides by -1:

x = 39/74 - sqrt(1817)/74 or y - 257/74 = -sqrt(1817)/74

Add 257/74 to both sides:

x = 39/74 - sqrt(1817)/74 or y = 257/74 - sqrt(1817)/74

Substitute back for y = 4 - x:

x = 39/74 - sqrt(1817)/74 or 4 - x = 257/74 - sqrt(1817)/74

Subtract 4 from both sides:

x = 39/74 - sqrt(1817)/74 or -x = -39/74 - sqrt(1817)/74

Multiply both sides by -1:

Answer:  x = 39/74 - sqrt(1817)/74 or x = 39/74 + sqrt(1817)/74

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