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Soloha48 [4]
3 years ago
10

The sum of ten and the quotient of a number x and 6

Mathematics
2 answers:
levacccp [35]3 years ago
6 0

That expression can be written as:


\boxed{\bf~10+\frac{x}{6}}



Hope it helped,


Happy homework/ study/ exam!

mylen [45]3 years ago
6 0

That expression, in numbers, will be:


10 + x/6


Hope it helped,


Happy homework/ study/ exam!

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WHAT IS S=2PIR^2+2PIRH SOLVE FOR H
grigory [225]
\\~\qquad\quad S\ =\ 2PIR^2+2PIRH\\\underline{-2PIR^2\qquad-2PIR^2\qquad\quad\ }\\\\ S-2PIR^2=2PIRH\\\\ 2PIRH\ =\ S-2PIR^2\\\underline{ :(2PIR)\qquad :(2PIR)}\\\\\\ H=\dfrac{S-2PIR^2}{2PIR}\\\\\\ H=\dfrac{S}{2PIR}-\dfrac{2PIR^2}{2PIR}\\\\\\ H=\dfrac{S}{2PIR}-R


or:

\\~\qquad\quad S\ =\ 2PIR^2+2PIRH\\\\~\qquad\quad S\ =\ 2PIR(R+H)\\\underline{:(2PIR)\qquad :(2PIR)}\\\\\\~\ \  \dfrac{S}{2PIR}\ =\ R+H\\\\\\ \dfrac{S}{2PIR}-R=H\\\\\\ H=\dfrac{S}{2PIR}-R
4 0
3 years ago
In triangle ABC, E is the midpoint of AC and D is the midpoint of CB. if DF is parallel to BE, find the length of side AB.
ankoles [38]
Δ FCD is a right triangle ( 3² + 4² + 5² ).
10 : EB = 5 : 3
5 EB = 30
EB = 6
With Pythagorean theorem:
CE² = 10² - 6² = 10 - 36 = 64
CE = 8
ED = 5
AB = 2 · 5 = 10
Answer: The length of the side AB is 10. 
5 0
3 years ago
Read 2 more answers
Plzzzzzzzzzzzzzzz help what is 6+x÷3=13
saveliy_v [14]

Answer:


Step-by-step explanation:


3 0
3 years ago
Read 2 more answers
X^2+_x+_=0<br> Please help need to pass this class
snow_tiger [21]
Answer:
x^2+0x+(-x^2)=0

Explanation:
x^2+0x+(-x^2)=0
Anything multiplied by 0 is equal to 0
x^2+0+(-x^2)=0
x^2+(-x^2)=0
A positive and a negative makes a negative
x^2-x^2=0
0=0

For these types of problems, play around with multiplying by 0 and adding negatives.

I hope this helps! Please comment if you have any questions.
7 0
3 years ago
Rewrite the expression with a perfect square: x^2 - 14x + 11
nikitadnepr [17]

   Factoring  x2-14x+11 

The first term is,  x2  its coefficient is  1 .

The middle term is,  -14x  its coefficient is  -14 .

The last term, "the constant", is  +11 

Step-1 : Multiply the coefficient of the first term by the constant   1 • 11 = 11 

Step-2 : Find two factors of  11  whose sum equals the coefficient of the middle term, which is   -14 .

     -11   +   -1   =   -12     -1   +   -11   =   -12     1   +   11   =   12     11   +   1   =   12

Observation : No two such factors can be found

4 0
3 years ago
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