C' (-6,3)
A 90 degree rotation counterclockwise around point A'
9514 1404 393
Answer:
∠Q = 89°
∠R = 123°
∠S = 91°
Step-by-step explanation:
It seems easiest to start by finding the measures of each of the arcs. The measure of an arc is double the measure of the inscribed angle it subtends.
arc QRS = 2·∠P = 114°
So, ...
arc QR = arc QRS - arc RS = 114° -41° = 73°
The total of the arcs around the circle is 360°, so ...
arc PQ = 360° -arc PS -arc QRS
arc PQ = 360° -137° -114° = 109°
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∠Q = (1/2)(arc RS + arc PS) = (1/2)(41° +137°)
∠Q = 89°
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∠R = (1/2)(arc PS +arc PQ) = (1/2)(137° +109°)
∠R = 123°
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∠S = (1/2)(arc PQ +arc QR) = (1/2)(109° +73°)
∠S = 91°
Area of the trapezoid = 1/2(B+b)h
where
B= length of the longer side of the trapezoid which is equal to 14 ft
b= shorter shorter side of the trapezoid which equal 8 ft
h = height of the trapezoid which is equal to 4 ft
Area of the trapezoid = 1/2 (14+8)4
Area of the trapezoid yard fence of Duc is 44ft^2
