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2 years ago

The sum of ten and the quotient of a number x and 6

Mathematics

2 answers:

levacccp [35]2 years ago

6 0

That expression can be written as:

$\boxed{\bf~10+\frac{x}{6}}$

Hope it helped,

Happy homework/ study/ exam!

mylen [45]2 years ago

6 0

That expression, in numbers, will be:

10 + x/6

Hope it helped,

Happy homework/ study/ exam!

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There are two boxes containing only purple and yellow pens.

UNO [17]

Answer:

I'm not sure what the question is asking here

6 0

2 years ago

A 10-foot ladder leans against a wall with its foot braced 3 feet from wallÍs base. How far up the wall does the ladder reach?

iren2701 [21]

The answer is √91 feet (which is the same as 9.54 feet).

Imagine this as a right triangle. A length of the foot is actually a hypotenuse (c). The distance from wall's base to the ladder foot is one of the sides of the triangle (let it be a).
So, using the Pythagorean theorem:
c² = a² + b²
It is given:
c = 10 feet
a = 3 feet
b = ?
c² = a² + b²
⇒ 10² = 3² + b²
100 = 9 + b²
b² = 100 - 9 = 91
⇒ b = √b² = √91 ≈ 9.54 feet

5 0

2 years ago

I need help solving these problems

Delicious77 [7]

QUESTION 1

$4 {p}^{2} = 2 \times 2\times {p} \times p$

QUESTION 2

$39 {b}^{3} {c}^{2} = 3 \times 13 \times {b} \times b \times b\times {c} \times c$

QUESTION 3

$100 {x}^{3} y {z}^{2} = {2} \times 2 \times {5} \times 5 \times {x} \times x \times x\times y \times {z} \times z$

QUESTION 4

$66 {d}^{4} = 2 \times 3 \times 11 \times {d} \times d \times d \times d$

QUESTION 5

$85 {x}^{2} {y}^{2} = 5 \times 17 \times {x} \times x \times {y} \times y$

QUESTION 6

$18xy = 2 \times {3}^{2} \times x \times y$

$36 {y}^{2} = {2}^{2} \times {3}^{2} \times {y}^{2}$

The greatest common factor is the product of the least powers of the common factors;

$GCF=2 \times {3}^{2} \times y$

$GCF=18y$

QUESTION 7

$25mn = {5}^{2} \times m \times n$

$21m = 3 \times 7 \times m$

$GCF=m$

QUESTION 8

$15a = 3 \times 5 \times a$

$28a {b}^{2} = {2}^{2} \times 7 \times a \times {b}^{2}$

$GCF=a$

QUESTION 9

$24 {d}^{2} = {2}^{3} \times 3 \times {d}^{2}$

$30 {c}^{2} d = 2 \times 3 \times 5 \times d$

$GCF=2 \times 3 \times d$

$GCF=6d$

QUESTION 10

$20gh = {2}^{2} \times 5 \times g \times h$

$36 {g}^{2} {h}^{2} = {2}^{2} \times {3}^{2} \times {g}^{2} \times {h}^{2}$

$GCF= {2}^{2} \times g \times h$

$GCF=4gh$

QUESTION 11

$17 {c}^{3} {d}^{2} = 17 \times {c}^{3} \times {d}^{2}$

$5 {c}^{2} {d}^{2} = 5 \times {c}^{2} \times {d}^{2}$

$GCF= {c}^{2} \times {d}^{2}$

$GCF= {c}^{2}{d}^{2}$

4 0

2 years ago

Evaluate the function f\left(x\right)=5x+2\mid11-5x\mid-4f(x)=5x+2∣11−5x∣−4 for x = -5.

Anestetic [448]

Answer:

$f\left(5\right) = 43$

Step-by-step explanation:

Given

$f\left(x\right)=5x+2\mid11-5x\mid-4$

Required

Solve for x = -5

This implies that we substitute -5 for x in $f\left(x\right)=5x+2\mid11-5x\mid-4$

$f\left(5\right)=5(-5)+2\mid11-5(-5)\mid-4$

Open all brackets

$f\left(5\right) = -25+2\mid11+25\mid-4$

$f\left(5\right) = -25+2\mid36\mid-4$

Absolute value of 36 is 36; Wo, we have:

$f\left(5\right) = -25+2*36-4$

$f\left(5\right) = -25+72-4$

$f\left(5\right) = 43$

7 0

2 years ago

Help me please

kari74 [83]

Answer:

$\frac{ \cos(80) }{ \sin(10) } + \frac{ \sin(20) }{ \cos(70) } = 2 \\ \frac{ \cos(90 - 10) }{ \sin(10) } + \frac{ \sin(20) }{ \cos(9 0 - 20) } = 2 \\ \frac{ \sin(10) }{ \sin(10) } + \frac{ \sin(20) }{ \sin(20) } = 2 \\ 1 + 1 = 2 \\ 2 = 2 \\ \\ \frac{ \cot(40) }{ \tan(50) } + \frac{ \cos(65) }{ \sin(115) } = 2 \\ \frac{ \cot(90 - 50) }{ \tan(50) } + \frac{ \cos(65) }{ \sin(90 + 65) } = 2 \\ \frac{ \tan(50) }{ \tan(50) } + \frac{ \cos(65) }{ \cos(65) } = 2 \\ 1 + 1 \\ = 2$

6 0

2 years ago