Find the value of x.

Find the Discriminant, and determine the number of roots

scoundrel [369]

D I’m 50% sure I searched it up 2

8 0

3 years ago

100 points t who answers first and if answered right u will get brainiest ok

Grace [21]

Answer:

side c = 150 feet of flowers

Area = 5400 feet squared

concert question:

The converse of the Pythagorean theorem can help you determine whether the roped off area is in the shape of a right triangle because you use the side lengths of each square and enter them into the equation, and if the equation is true, then it is a right triangle

Concession stand question:

The school banner can fit across the length of the concession stand

the following information is missing

The length if the sides: c is 50 feet long, b is 40 foot long, and a is 30-foot long.

The distance between the two red stars of the picture makes the hypotenuse of a right triangle, where two sides of length a (30 ft) are the legs. From Pythagorean theorem, diagonal of square A is:

diagonal² = 30² + 30²

diagonal = √1800 = 42.43 ft

which is longer than the banner.

Blueprint question:

No, diagonal of square C is 70.71ft

2nd blueprint question:

50 square root 2

Gardening group:

50.24 yards

8 0

3 years ago

Read 2 more answers

If f(x) varies directly with x and f(x)=40 when x=8, find the value of f(x) when x=2.

melamori03 [73]

f(x)=40

x=8

so if x=2 it would be 40/8 which is 5

6 0

2 years ago

Read 2 more answers

7. Krista wrote a list of factors and a list

Lubov Fominskaja [6]

Answer:

3 is to 12, 5 is to 50, 7 is to 14, and 11 is to 22.

Step-by-step explanation:

4 0

3 years ago

Seventy-two percent of the light aircraft that disappear while in flight in a certain country are subsequently discovered. Of th

Anton [14]

Answer:

a) 0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) 0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) 0.064 = 6.4% probability that 7 of them are discovered.

Step-by-step explanation:

For itens a and b, we use conditional probability.

For item c, we use the binomial distribution along with the conditional probability.

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

a) If it has an emergency locator, what is the probability that it will not be discovered?

Event A: Has an emergency locator

Event B: Not located.

Probability of having an emergency locator:

66% of 72%(Are discovered).

20% of 100 - 72 = 28%(not discovered). So

$P(A) = 0.66*0.72 + 0.2*0.28 = 0.5312$

Probability of having an emergency locator and not being discovered:

20% of 28%. So

$P(A cap B) = 0.2*0.28 = 0.056$

Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.056}{0.5312} = 0.105$

0.105 = 10.5% probability that it will not be discovered if it has an emergency locator.

b) If it does not have an emergency locator, what is the probability that it will be discovered?

Probability of not having an emergency locator:

0.5312 of having. So

$P(A) = 1 - 0.5312 = 0.4688$

Probability of not having an emergency locator and being discovered:

34% of 72%. So

$P(A \cap B) = 0.34*0.72 = 0.2448$

Probability:

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.2448}{0.4688} = 0.522$

0.522 = 52.2% probability that it will be discovered if it does not have an emergency locator.

c) If we consider 10 light aircraft that disappeared in flight with an emergency recorder, what is the probability that 7 of them are discovered?

p is the probability of being discovered with the emergency recorder:

0.5312 probability of having the emergency recorder.

Probability of having the emergency recorder and being located:

66% of 72%. So

$P(A \cap B) = 0.66*0.72 = 0.4752$

Probability of being discovered, given that it has the emergency recorder:

$p = P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.4752}{0.5312} = 0.8946$

This question asks for P(X = 7) when $n = 10$ . So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 7) = C_{10,7}.(0.8946)^{7}.(0.1054)^{3} = 0.064$

0.064 = 6.4% probability that 7 of them are discovered.

8 0

3 years ago