Solve 2(x-3)=1-5(2-x)

In a company, 80% of the workers are women. If 480 men work for the company, how many workers are there in all? Use pencil

nekit [7.7K]

Answer:

The total workers are 2400.

Step-by-step explanation:

Given:

In company 80% of the workers are women.

480 workers are men.

Now, to find the total workers in all.

In first way:

If women are 80%, then men would be 100-80 = 20%.

Let the total workers be $x$ .

According to question:

$20\%\ of \ x=480$

⇒ $\frac{20}{100} \times x=480$

⇒ $0.20\times x=480$

⇒ $0.20x=480$

Dividing both sides by 0.20 we get:

⇒ $x=2400$ .

Total workers = 2400.

Now, in second way.

Again, let the total workers be $x$ .

According to question:

$x-80\%\ of\ x=480$

⇒ $x-\frac{80}{100}\times x=480$

On solving:

⇒ $x-0.80x=480$

⇒ $0.20x=480$

Dividing both sides by 0.20 we get:

⇒ $x=2400$ .

Total workers = 2400.

Therefore, the total workers are 2400.

7 0

3 years ago

Each student at some college has a mathematics requirement M (to take at least one mathematics course) and a science requirement

Furkat [3]

all students = 150

M = 60

S = 45

M and S = 25

(a) At least one of the two requirements:

M or S = M + S - (M and S) = 60 + 45 - 25 = 80

(b) Exactly one of the two requirements:

(M or S) - (M and S) = 80 - 25 = 55

(c) Neither requirement:

(all students) - (M or S) = 150 - 80 = 70

8 0

3 years ago

Answer.

zalisa [80]

The Malcontents' major complaints were that the Trustees had placed too many limitations on the ownership of land, the right to make and to buy alcohol, and the right to own slaves.

5 0

3 years ago

Read 2 more answers

An educational psychologist wishes to know the mean number of words a third grader can read per minute. She wants to make an est

MrRa [10]

Answer:

85% level of the confidence interval is

(26.337, 26.662)

Step-by-step explanation:

Explanation:-

Given the size of the sample 'n' = 295

Mean of the sample x⁻ = 26.5

The Standard deviation of the Population = 2.7

85% level of the confidence interval is determined by

$(x^{-} - Z_{0.15} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.15} \frac{S.D}{\sqrt{n} })$

Critical value Z₀.₁₅ = 1.036

85% level of the confidence interval is determined by

$(x^{-} - Z_{0.15} \frac{S.D}{\sqrt{n} } , x^{-} + Z_{0.15} \frac{S.D}{\sqrt{n} })$

$(26.9 -1.036 \frac{2.7}{\sqrt{295} } , 26.5 + 1.036 \frac{2.7}{\sqrt{295} })$

( 26.5 - 0.1628 , 26.5+0.1628)

(26.3372,26.6628)

7 0

3 years ago

The math club is selling T-shirts to raise money. Each T-shirt sold represents a profit of $2. The club has a total of 500 T-

vova2212 [387]

Answer:

2 < or equal to (t) < or equal to 1000

Step-by-step explanation:

2 is the profit of the (t) amount of t shirts so the amount should be greater than or equal too 1000 because if they have 500 shirts 500 x 2 is 1000

3 0

2 years ago