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2 years ago

11

A model car is 6.9 centimeters long and 3.5 centimeters wide. find the real length of the car. Round your answer to the nearest

tenth

1 answer:

Rasek [7]2 years ago

4 0

Answer: I'm pretty sure its 10.4 but I may be wrong

Step-by-step explanation: hopefully I helped you

You might be interested in

Find the 14th term of the geometric sequence 3,6,12,24.

jekas [21]

An=a1(r)^(n-1)
a1=first term
r=common rati

common ratio is a term divded by previous term
6/3=2
r=2

first term is 3

an=3(2)^(n-1)
14th term
a14=3(2)^(14-1)
a14=3(2)^13
a14=3(8192)
a14=24576

the 14th term is 24576

5 0

3 years ago

Mason walked on Monday, Wensday, and Friday. Use these clues to find how far he walked each day. These distances were six-eights

krok68 [10]

Answer:

Monday he walked $\frac{1}{4}miles$

Wednesday he walked $\frac{6}{8}miles$

Friday he walked $\frac{1}{6}miles$

Step-by-step explanation:

Given Mason walked on Monday, Wednesday and Friday. These distances were six-eights mile, one-fourth mile, and one-sixth mile. He did not walk the farthest on Monday. He walked less on Friday than Monday. we have to find how far he walked each day.

distances are $\frac{6}{8}, \frac{1}{4}, \frac{1}{6}$ that are 0.75, 0.25 and 0.17 respectively.

Now, he didn't walk farthest on Monday and also walked less on Friday than Monday.

∴ Less distance travelled is $\frac{1}{6}$ which is on friday and then $\frac{1}{4}$ on monday.

Rest distance which is $\frac{6}{8}$ on wednesday.

Hence, Monday he walked $\frac{1}{4}miles$

Wednesday he walked $\frac{6}{8}miles$

Friday he walked $\frac{1}{6}miles$

4 0

3 years ago

Read 2 more answers

Check all solutions to the equation. If there are no solutions, check "None."

Margaret [11]

X can be 4 or -4

As a minus by a minus is a positive

8 0

2 years ago

PLEASE HELPPPPP ASAP

saul85 [17]

Answer:

it's the last one, the function is decreasing from x=-3 to x=-1

5 0

2 years ago

?? So lost with this

labwork [276]

Answer:

$A)\ 1,\ -1,\ -3\\\\B)\ d=-2\\\\C)\ \left\{\begin{array}{ccc}a_1=11\\a_n=a_{n-1}-2\end{array}\right\\\\D)\ f(n)=-2n+13$

Step-by-step explanation:

It's an arithmetic sequence.

9 = 11 - 2

7 = 9 - 2

5 = 7 - 2

3 = 5 - 2

A) next three terms: 3 - 2 = 1, 1 - 2 = -1, -1 - 2 = -3

B) Common difference = -2

C) Recursive Function:

$\left\{\begin{array}{ccc}a_1=11\\a_n=a_{n-1}-2\end{array}\right$

D) Explicit Function:

$f(n)=a_1+(n-1)d$

a₁ - first term

d - common difference

Substitute a₁ = 11 and d = -2:

$f(n)=11+(n-1)(-2)=11-2n+2=-2n+13$

4 0

3 years ago