Answer:
D) -20/-5 because a negative divided by a negative is a positive.
Step-by-step explanation:
What do they mean by describe the diagram
Answer:
Step-by-step explanation: 14
Simplify ——
x :
14
(2x - ——) - 7
x
Answer:
(x-1)^2+(y+1)^2=3
Step-by-step explanation:
x² + y2 - 2x + 2y - 1 = 0
add the 1 to get it to the other side of the equation
x² + y2 - 2x + 2y = +1
group the x's and y's
(x² -2x) + (y2+2y) = +1
then you'll complete the square on the -2x and + 2y. that just means divide by two and then raise it to the 2nd power.
so (-2/2)^2 and (+2/2)^2
(x²-2x+1)+(y2+2y+1) = 1+1+1
you add the one's to the other side because whatever is done to one side must be done to the other
you'll then need to factor again.
(x-1)^2+(y+1)^2=3
to factor it take one of your squared x's, the sign of the middle term within the parentheses , then the square root of the last term within the parentheses. remeber to put your ^2 (raised to the 2nd power) outside of the parentheses when you finish.
Answer:
- P(≥1 working) = 0.9936
- She raises her odds of completing the exam without failure by a factor of 13.5, from 11.5 : 1 to 155.25 : 1.
Step-by-step explanation:
1. Assuming the failure is in the calculator, not the operator, and the failures are independent, the probability of finishing with at least one working calculator is the complement of the probability that both will fail. That is ...
... P(≥1 working) = 1 - P(both fail) = 1 - P(fail)² = 1 - (1 - 0.92)² = 0.9936
2. The odds in favor of finishing an exam starting with only one calculator are 0.92 : 0.08 = 11.5 : 1.
If two calculators are brought to the exam, the odds in favor of at least one working calculator are 0.9936 : 0.0064 = 155.25 : 1.
This odds ratio is 155.25/11.5 = 13.5 times as good as the odds with only one calculator.
_____
My assessment is that there is significant gain from bringing a backup. (Personally, I might investigate why the probability of failure is so high. I have not had such bad luck with calculators, which makes me wonder if operator error is involved.)
