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3 years ago

Subtract these polynomials (3x^2x+4)-(x^2+2x+1)

Mathematics

2 answers:

harina [27]3 years ago

6 0

2x^2+3. the 2x cancel out and the rest is combining like terms

Aleks04 [339]3 years ago

3 0

Answer:

(with a + between 2 and x in the first polynomial) 2x^2-x+3

Step-by-step explanation:

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Add these fractions just pretend / means fraction

CaHeK987 [17]

Answer is 16 1/3. hope that helps

8 0

3 years ago

Jean estimates that her friend completes a new level of a video game on the first try 20% of the time. She conducts a simulation

Rainbow [258]

The probability of the friend completing the new level in her first try is 22.5%

<h3>What is probability?</h3>

This is a concept that is used to talk about the likelihood or the chances of an event occuring.

For the digit 8, the frequency is 7

For the digit 9, the frequency is 11

The total number of frequencies is given as

10 + 9 + 6+ 7 + 8 + 12 + 4 + 6 + 7 + 11 = 80

7 + 11 = 18

Probability = 18/80

= 0.225 x 100

= 22.5%

Read more on probability here: brainly.com/question/251701

8 0

2 years ago

What happening to this graph when x-values are between -8 and -4

agasfer [191]

Not sure, there is no graph with it. I just edited the question to fix the formatting and to add in info that got cut off when iI pasted it in.

7 0

3 years ago

I really need help, please

solong [7]

Answer:

C: $\frac{5}{2} + \frac{1}{2} i$

Step-by-step explanation:

Did this through my TI-89 calculator. ^^

6 0

3 years ago

The town of Hayward (CA) has about 50,000 registered voters. A political research firm takes a simple random sample of 500 of th

Ilia_Sergeevich [38]

Answer:

(0.0757;0.1403)

Step-by-step explanation:

1) Data given and notation

Republicans =115

Democrats=331

Independents=54

Total= n= 115+331+54=500

$\hat p_{ind}=\frac{54}{500}=0.108$

Confidence=0.98=98%

2) Formula to use

The population proportion have the following distribution

$\hat p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The confidence interval for the population proportion is given by this formula

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}$

We have the proportion of independents calculated

$\hat p_{ind}=\frac{54}{500}=0.108$

We can calculate $\alpha=1-conf=1-0.98=0.02$

And we can find $\alpha/2 =0.02/2=0.01$ , with this value we can find the critical value $z_{\alpha/2}$ using the normal distribution table, excel or a calculator.

On this case $z_{\alpha/2}=2.326$

3) Calculating the interval

And now we can calculate the interval:

$0.108 - 2.326\sqrt{\frac{0.108(1-0.108)}{500}}=0.0757$

$0.108 + 2.326\sqrt{\frac{0.108(1-0.108)}{500}}=0.1403$

So the 98% confidence interval for this case would be:

(0.0757;0.1403)

7 0

3 years ago