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Misha Larkins [42]
3 years ago
7

Lines k and p are perpendicular, neither is vertical and p passes through the origin. Which is greater? A. The product of the sl

opes of lines k and p B. The product of the y-intercepts of lines k and p
Mathematics
1 answer:
AlladinOne [14]3 years ago
4 0
What do we know about those two lines?

They are perpendicular, meaning they have the same slope.
We know the slope of both is not zero (neither is vertical).
Therefore either
1) Both slopes are positive and therefore the product is positive
2) Both slopes are negative and therefore the product is positive (minus by a minus is a plus)

For the y intercepts, we know that the line P passes through the origin.
Therefore its Y intercept is zero.
[draw it if this is not obvious and ask where does it cross the y axis]
Therefore the Y intercept of line K and line P is zero.
[anything multiplied by a zero is a zero]

So we know that the product of slopes is positive, and we know that the product of Y intercepts is zero.
So the product of slopes must be greater.
Answer A
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Help me again please​
mash [69]

Answer:

answer C (0,-9)

Step-by-step explanation:

the line passes through (0,-9)

6 0
3 years ago
Please help!! <br> Solve the system using an augmented matrix. Show all work
marishachu [46]

Answer:

<em>The solution of the system is:  x=2, y=5</em>

Step-by-step explanation:

The given system of equations is.......

-x-3y=-17\\ \\ 2x-6y=-26

So, the augmented matrix will be:   \left[\begin{array}{cccc}-1&-3&|&-17\\2&-6&|&-26\\\end{array}\right]

Now, we will transform the augmented matrix to the reduced row echelon form using row operations.

<u>Row operation 1 :</u>  Multiply the 1st row by -1. So..........

\left[\begin{array}{cccc}1&3&|&17\\2&-6&|&-26\\\end{array}\right]

<u>Row operation 2:</u>  Add -2 times the 1st row to the 2nd row. So.......

\left[\begin{array}{cccc}1&3&|&17\\0&-12&|&-60\\\end{array}\right]

<u>Row operation 3:</u>  Multiply the 2nd row by -\frac{1}{12}. So.......

\left[\begin{array}{cccc}1&3&|&17\\0&1&|&5\\\end{array}\right]

<u>Row operation 4:</u>  Add -3 times the 2nd row to the 1st row. So........

\left[\begin{array}{cccc}1&0&|&2\\0&1&|&5\\\end{array}\right]

Now, from this reduced row echelon form of the augmented matrix, we can get that x=2 and y=5

So, the solution of the system is:  x=2, y=5

8 0
3 years ago
A.
Oliga [24]
I’m not sure what the answer is, just trying to get points.... but I hope you find your answer :)
4 0
3 years ago
Cos^2(2theta)+ 2cos(2theta)+1=0
Tema [17]

Answer:

θ = π n + π/2 for n element Z

Step-by-step explanation:

Solve for θ:

1 + 2 cos(2 θ) + cos^2(2 θ) = 0

Write the left hand side as a square:

(cos(2 θ) + 1)^2 = 0

Take the square root of both sides:

cos(2 θ) + 1 = 0

Subtract 1 from both sides:

cos(2 θ) = -1

Take the inverse cosine of both sides:

2 θ = 2 π n + π for n element Z

Divide both sides by 2:

Answer:  θ = π n + π/2 for n element Z

4 0
3 years ago
Balance the following : <br>K + H20----------&gt; KOH +H2<br>please help fast I'm giving an exam​
Elza [17]

Step-by-step explanation:

2K + 2H2O ➡ 2KOH + H2

Hope it helps :)

7 0
3 years ago
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