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Neko [114]
3 years ago
5

Solve for x. 25x=65 1225 125 3 6

Mathematics
2 answers:
NARA [144]3 years ago
8 0

25x = 65
Divide both sides by 25 to isolate x:

\frac{25x}{25}  =  \frac{65}{25}  \\  \\ x =  \frac{13}{5}  = 2.6
Akimi4 [234]3 years ago
4 0
<h2>Option C is the correct answer.</h2>

Step-by-step explanation:

We need to find 25 x = 65

Dividing both sides by 25

We will get

                25x=65\\\\\frac{25x}{25}=\frac{65}{25}\\\\x=\frac{13\times 5}{5\times 5}\\\\x=\frac{13}{5}\\\\x=2.6\\\\x\approx 3

Option C is the correct answer.

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Given:
diamong [38]

Answer:

10-5\sqrt{2}

Step-by-step explanation:

As per the attached figure, right angled \triangle MDL has an inscribed circle whose center is I.

We have joined the incenter I to the vertices of the \triangle MDL.

Sides MD and DL are equal because we are given that \angle M = \angle L = 45 ^\circ.

Formula for <em>area</em> of a \triangle = \dfrac{1}{2} \times base \times height

As per the figure attached, we are given that side <em>a = 10.</em>

Using pythagoras theorem, we can easily calculate that side ML = 10\sqrt{2}

Points P,Q and R are at 90 ^\circ on the sides ML, MD and DL respectively so IQ, IR and IP are heights of  \triangleMIL, \triangleMID and \triangleDIL.

Also,

\text {Area of } \triangle MDL = \text {Area of } \triangle MIL +\text {Area of } \triangle MID+ \text {Area of } \triangle DIL

\dfrac{1}{2} \times 10 \times 10 = \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10 + \dfrac{1}{2} \times r \times 10\sqrt2\\\Rightarrow r = \dfrac {10}{2+\sqrt2} \\\Rightarrow r = \dfrac{5\sqrt2}{\sqrt2+1}\\\text{Multiplying and divinding by }(\sqrt2 +1)\\\Rightarrow r = 10-5\sqrt2

So, radius of circle = 10-5\sqrt2

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Answer:

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Step-by-step explanation:

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