The first answer is 5,but i don't know about the second one. (sorry)
Problem 7: Correct
Problem 8: Correct
Problem 9: Correct
The steps are below if you are curious
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Problem 7
S = 180*(n-2)
2340 = 180*(n-2)
2340/180 = n-2
13 = n-2
n-2 = 13
n = 13+2
n = 15
I'm using n in place of lowercase s, but the idea is the same. If anything, it is better to use n for the number of sides since S already stands for the sum of the interior angles. I'm not sure why your teacher decided to swap things like that.
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Problem 8
First find y
y+116 = 180
y+116-116 = 180-116
y = 64
which is then used to find x. The quadrilateral angles add up to 180*(n-2) = 180*(4-2) = 360 degrees
Add up the 4 angles, set the sum equal to 360, solve for x
x+y+125+72 = 360
x+64+125+72 = 360 ... substitution (plug in y = 64)
x+261 = 360
x+261-261 = 360-261
x = 99
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Problem 9
With any polygon, the sum of the exterior angles is always 360 degrees
The first two exterior angles add to 264. The missing exterior angle is x
x+264 = 360
x+264-264 = 360-264
x = 96
This one is a bit more complicated but i believe the answer is -1/4
Answer:
y=83333728267=९%--#7*$-#-4-!
Answer:
Domain = 1 to 7
Range = 4 to 28
Step-by-step explanation:
Given that:
Number of wheels used is a function of number of cars manufactured.
Number of wheels present = 28
1 car uses 4 wheels
2 cars use 8 wheels.
3 car uses 12 wheels
and so on.
Let the function be of the form:

Domain of the function is the value of
that can be given as valid input to the function.
Range of the function is the value of
that can be output of the function.
Let
be the number of cars manufactured.
Then value of
is nothing but
times 4.

We are given that maximum value of
can be 28.

Therefore, maximum value of input can be 7.
Minimum number of wheels can be 4 to make a minimum of 1 car.
Therefore domain is 4 to 28 and range is 1 to 7.