Answer:
=5/21L+ -5/84
Step-by-step explanation:
=-(5/7) (-(1L/3-3/4)+1/3/4)
=(-5/7)(-(1L/3-3/4))+(-5/7)(1/3/4)
=5/21L= -15/28+ -5/84
=5/21L=+ -25/42
Answer:
a. 15/23
b. 13/27
c. 400g
Step-by-step explanation:
a. When the denominators are the same, you can just sum the numerators.
Which becomes, 13+2=15--> 15/23
b. Same, when the denominator is the same, you can just minus the numerators. Which becomes, 25-12=13--> 13/27
c. 1kg=1000g. 1000/5=200✖️2=400
(5+22)x(35-27)+6x6
27 (35-27)+6x6
27x8+6x6
27x7+36
216+36
=252
The probability that the cube never lands on 3 is (D) 23.3%.
<h3>
What is probability?</h3>
- A probability formula can be used to calculate the likelihood of an occurrence by simply dividing the favorable number of possibilities by the entire number of possible outcomes.
To find the probability that the cube never lands on 3:
Given -
Required
- Probability of not landing on 3.
First, we need to get the probability of landing on 3 in a single toss.
For a number cube,
- n(3) = 1 and n(total) = 6
So, the probability is P(3) = 1/6
First, we need to get the probability of not landing on 3 in a single toss.
Opposite probability = 1.
Make P(3') the subject of the formula.
- P(3') = 1 - P(3)
- P(3') = 1 - 1/6
- P(3') = 5/6
In 8 toss, the required probability is (P(3'))⁸
This gives:
- P = (5/6)⁸
- P = 390625/1679616
- P = 0.23256803936
Approximate to 1 decimal place, P = 23.3%.
Therefore, the probability that the cube never lands on 3 is (D) 23.3%.
Know more about probability here:
brainly.com/question/25870256
#SPJ4
The correct question is given below:
A number cube is tossed 8 times. What is the probability that the cube never lands on 3?
A. 6.0%
B. 10.4%
C. 16.7%
D. 23.3%
<span>(4⋅a)⋅2
= 8a
hope it helps</span>
