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lozanna [386]
3 years ago
15

Given DA=5, A F=8, KE=x, and EF=12. What must the value of x be in order to prove AE||KD?​

Mathematics
1 answer:
aksik [14]3 years ago
3 0

Answer:

The answer to your question is x = 7.5

Step-by-step explanation:

Process

I inserted the answer as an image because it said that I was writing inappropriate words.

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I think proprietorship if wrong i am sorry

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2 years ago
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HEL----PPPPpppppppppppppppppppppppppppppp
omeli [17]

Answer:

Step-by-step explanation:

First order from smallest to largest.

70.8, 71.9, 72.1, 82.4, 85.3, 98.1.

Median is the middle number/s.

72.1+82.4/2 so The median is 77.25

Range is the largest number minus the smallest number.

85.3-70.8=14.5

Mode is the most repeated number.

Since there are no repeated numbers there is no mode.

Second question:

Again rearrage: 6, 9, 11, 14, 17

In order to make the median 10 you would have to add another 9 becasue

11+9/2 = 10

Third: remove 6 to make 12 the middle number

Fourth: add all numbers 90+x/6=20 so x has to be 30

8 0
3 years ago
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F(x) = <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%2B7%7D%20-%5Csqrt%7Bx%5E2%2B2x-15%7D" id="TexFormula1" title="\sqrt{x+7} -\
elena-s [515]

Answer:

x >= -7  ................(1a)

x >= 3   ...............(2a1)

Step-by-step explanation:

f(x) =  \sqrt{x+7}-\sqrt{x^2+2x-15}  .............(0)

find the domain.

To find the (real) domain, we need to ensure that each term remains a real number.

which means the following conditions must be met

x+7 >= 0  .....................(1)

AND

x^2+2x-15 >= 0 ..........(2)

To satisfy (1),  x >= -7  .....................(1a) by transposition of (1)

To satisfy (2), we need first to find the roots of (2)

factor (2)

(x+5)(x-3) >= 0

This implis

(x+5) >= 0 AND (x-3) >= 0.....................(2a)

OR

(x+5) <= 0 AND (x-3) <= 0 ...................(2b)

(2a) is satisfied with x >= 3   ...............(2a1)

(2b) is satisfied with x <= -5 ................(2b1)

Combine the conditions (1a), (2a1), and (2b1),

x >= -7  ................(1a)

AND

(

x >= 3   ...............(2a1)

OR

x <= -5 ................(2b1)

)

which expands to

(1a) and (2a1)   OR  (1a) and (2b1)

( x >= -7 and x >= 3 )  OR ( x >= -7 and x <= -5 )

Simplifying, we have

x >= 3  OR ( -7 <= x <= -5 )

Referring to attached figure, the domain is indicated in dark (purple), the red-brown and white regions satisfiy only one of the two conditions.

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3 years ago
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Answer:

302.33

Step-by-step explanation:

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The perimeter of a rectangle is 84cm if the width of rectanle is 16 cm Find its lenth.
Gelneren [198K]
To find the perimeter it is 2 X Width + 2 X the length = 84

32+ 2 X the length = 84
2 X the length = 52
Therefore the length is 26cm
4 0
2 years ago
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