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lozanna [386]
3 years ago
15

Given DA=5, A F=8, KE=x, and EF=12. What must the value of x be in order to prove AE||KD?​

Mathematics
1 answer:
aksik [14]3 years ago
3 0

Answer:

The answer to your question is x = 7.5

Step-by-step explanation:

Process

I inserted the answer as an image because it said that I was writing inappropriate words.

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Solve the system of equation
nikdorinn [45]

Answer:

So the Point of intersection is (-4,-2)

Which is option A

Step-by-step explanation:

The given system of equations is

-0.1x - 0.8y = 2              ...................(i)

0.6x - 0.5y = -1.4           ...................(ii)

Let us take equation (i) and use method of substitution for solving it

the equation (i) is

-0.1 x - 0.8y = 2

Adding 0.8y on both sides

-0.1 x + 0.8 y - 0.8 y = 2 + 0.8 y

-0.1 x = 2 + 0.8 y

Dividing both sides -0.1

\frac{-0.1 x}{-0.1}=\frac{0.8 y}{-0.1}+\frac{2}{-0.1}

x = -8 y - 20                     ..........................(iii)

Now we will use this value and put it into equation (ii) to find the value of y

Equation (ii) is

0.6 x - 0.5 y = -1.4

Put value of x

0.6(-8 y - 20) - 0.5 y =-1.4

It becomes

-4.8 y - 12 - 0.5 y = -1.4

adding 12 on both sides

-4.8 y - 0.5 y - 12 + 12 = -1.4 + 12

it becomes by solving

-5.3 y = 10.6

Dividing both sides by -5.3

\frac{-5.3*y}{-5.3}=\frac{10.6}{-5.3}

So

y = -2

Now we have the value of y putting it in equation (iii)

Equation (iii) is

x = -8 y - 20    

Putting value of y

x = -8*(-2) - 20

x = 16-20

x=-4

So the Point of intersection is (-4,-2)

7 0
3 years ago
Ethan goes to the fair which costs $17.50 for admission and $2.25 for each ride Ethan cab spend no more than $45.50 write an equ
spin [16.1K]
I got this same exact question
3 0
3 years ago
Read 2 more answers
PLEASE SOLVEEEEEEE!!!!!!!!!!!!!!!!!!!!!!!!!!!
kaheart [24]
I think the answer is -6
6 0
3 years ago
Read 2 more answers
How do you write 0.236 in word form
Helen [10]
Two-hundred thirty six thousandths 

Hope this helps!
6 0
3 years ago
Given that the expression x³_ ax² + bx+c leaves the same remainder when divided by x + 1 or x-2, find 'a' in terms of 'b'.​
goblinko [34]

Answer:

Hi,

a=b+3

Step-by-step explanation:

\begin{array}{c||c|c|c|c}&x^3&x^2&x&1\\---&---&---&---&---\\&1&-a&b&c\\x=-1&&-1&a+1&-a-b-1\\---&---&---&---&---\\&1&-a-1&a+b+1&c-a-b-1\\\end{array}

\begin{array}{c||c|c|c|c}&x^3&x^2&x&1\\---&---&---&---&---\\&1&-a&b&c\\x=2&&2&4-2a&2b+8-4a\\---&---&---&---&---\\&1&2-a&b+4-2a&c+2b+8-4a\\\end{array}

Thus:

c+2b+8-4a=c-a-b-1

3b-3a=-9

<u>a=b+3</u>

5 0
2 years ago
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