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3 years ago

Given DA=5, A F=8, KE=x, and EF=12. What must the value of x be in order to prove AE||KD?

Mathematics

1 answer:

aksik [14]3 years ago

3 0

Answer:

The answer to your question is x = 7.5

Step-by-step explanation:

Process

I inserted the answer as an image because it said that I was writing inappropriate words.

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1. Given line segment RB and on it is point C, if RB = 45 and CB = 3x - 12 and RC = 2x + 9, what is the value of x?

marshall27 [118]

Answer:

Step-by-step explanation:

1). If a point C is lying on a line segment RB,

Then RB = RC + CB

Since, RB = 45, CB = 3x - 12 and RC = 2x + 9

45 = (2x + 9) + (3x - 12)

45 = (2x + 3x) - 3

48 = 5x

x = $\frac{48}{5}$

x = 9.6

2). Since, RC = 2x + 9

RC = 2(9.6) + 9

= 19.2 + 9

= 28.2 units

3). Distance between the two points $(x_1,y_1)$ and $(x_2,y_2)$ is given by the formula,

d = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Distance between the points A(2, -2) and D(-2, 2) will be,

$AD=\sqrt{(2+2)^2+(-2-2)^2}$

= $\sqrt{16+16}$

= $4\sqrt{2}$

= 5.657

≈ 5.66 units

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2 years ago

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Given DA=5, A F=8, KE=x, and EF=12. What must the value of x be in order to prove AE||KD?​

Given DA=5, A F=8, KE=x, and EF=12. What must the value of x be in order to prove AE||KD?