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Serjik [45]
3 years ago
7

Two negative charges that are both -3.0 C push each other apart with a force of 19.2 N. How far apart are the two charges ?

Physics
1 answer:
fgiga [73]3 years ago
5 0
The Coulomb's force acting between two charges is
F=k_e  \frac{q_1 q_2}{r^2}
where k_e = 8.99 \cdot 10^9 N m^{-2}C^{-2} is the Coulomb's constant, q1 and q2 the two charges, and r the distance between them.

Using q_1 = q_2 = -3 C, we can find the distance between the two charges when the force is F=19.2 N:
r=  \sqrt{k_e  \frac{q_1 q_2}{F} }=  \sqrt{ 8.99\cdot 10^9 \frac{(-3.0C)^2}{19.2 N} }=6.5 \cdot 10^4 m = 65 km
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