Answer:
Explanation:
Given:
Initial velocity, u = 0 m/s (at rest)
Final velocity, v = 22 m/s
Time, t = 9 s
Diameter, d = 58 cm
Radius, r = 0.29 m
Using equation of motion,
v = u + at
a = (22 - 0)/9
= 2.44 m/s^2
v^2 = u^2 + 2a × S
S = (22^2 - 0^2)/2 × 2.44
= 99.02 m
S = r × theta
Theta = 99.02/0.29
= 341.44 °
1 rev = 360°
341.44°,
= 341.44/360
= 0.948 rev
= 0.95 rev
B.
Final angular speed, wf = v/r
= 22/0.29
= 75.86 rad/s
Answer:13.2,41.4,82.8 ft
Explanation:
Given Person is 6.60 ft from the left hand side mirror
Since the focal length of plane mirror is infinity therefore image and object are equidistant from mirror
Distance of first image on left mirror is
i.e. image is 13.2 ft away from object
Second image
Now the right mirror forms the image of object at distance of 14.1 ft right from right mirror so its image is formed in left mirror at a distance of 34.8 from left mirror
so image distance from person is
Third image now form image of second image is formed on right mirror at a distance of 55.5 right from right mirror
and its mirror image is formed on left mirror at a distance of 76.2 left
from left mirror
Answer:
weight on Venus = 604.15 N
weight on Venus = 252.01 N
Explanation:
Given:
Weight on the earth , W = 150 lbs
now,
1 lbs = 4.45 N
thus,
W = 150 × 4.45 = 667.5 N
now, mass on the earth, m = 667.5/9.8 = 68.11 kg
now,
⇒ weight on Venus,
the acceleration due to gravity on venus = 8.87 m/s²
thus,
weight on Venus = mass × acceleration due to gravity on venus
or
weight on Venus = 68.11 × 8.87 = 604.15 N
⇒ weight on mars,
the acceleration due to gravity on mars = 3.70 m/s²
thus,
weight on Venus = mass × acceleration due to gravity on venus
or
weight on Venus = 68.11 × 3.70 = 252.01 N
Answer:
b a model of water temperatures in the oceans
Explanation:
A conceptual model is a means of representing abstract theories, with the aim of helping the audience form mental pictures about the subject being discussed. Most of these models utilize diagrams to help form a better understanding of the subject.
In geothermal explorations, water temperatures can be represented using plane or cross sectional views to demonstrate the varying temperatures of water. This is a useful guidde in the exploration proceess and helps any who read the illustrations to form a better understanding of the process and conditions.
