Answer:You're selling tickets to a school play priced at $5 for students, $10 for parents, and $20 for general admission. The total sales are $2,500, you sell twice as many parent tickets as student tickets, and you selll 10 more students tickets than general admission. How many of each ticket did you sell?
Step-by-step explanation:
Answer:
D. (-2,-3)
Step-by-step explanation:
It's the answer
The solutions are
- it is going to take 15.9 months to raise 10000 dollars
- You will have $37.31 after you have bought the car
- The money deficit would be $37.31
<h3>How to solve the question</h3>
a. 10000 = 9359.08e(0.05)
e⁰⁰⁵ = 10000/9359.08
= 0.05 = ln(10000/9359.08)
= 1.325 years
convert to months = 15.9 months
Hence it is going to take 15.9 months to raise 10000 dollars
b. 9359.08 x e^(0.05 x1.25)
= 9962.69
10000 - 9962.69
= $37.31
You will have $37.31 after you have bought the car
c. The money loss and the deficit would be same as above $37.31
d. ln(e^a) = a
We can clearly see that the money cannot be raised in the 15 months from $ 9359.08. there is a deficit amount of $37.31
Read more on compound interest here: brainly.com/question/24924853
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Angle TRQ is 23 degrees and the length from S to R is 3.3 units.
I need help on this too
This pattern of question is always coming up. Since we can't easily guess, then let us set up simultaneous equation for the statements.
let the two numbers be x and y.
Multiply to 44. x*y = 44 ..........(a)
Add up to 12. x + y = 12 .........(b)
From (b)
y = 12 - x .......(c)
Substitute (c) into (a)
x*y = 44
x*(12 - x) = 44
12x - x² = 44
-x² + 12x = 44
-x² + 12x - 44 = 0.
Multiply both sides by -1
-1(-x² + 12x - 44) = -1*0
x² - 12x + 44 = 0.
This does not look factorizable, so let us just use quadratic formula
comparing to ax² + bx + c = 0, x² - 12x + 44 = 0, a = 1, b = -12, c = 44
x = (-b + √(b² - 4ac)) /2a or (-b - √(b² - 4ac)) /2a
x = (-(-12) + √((-12)² - 4*1*44) )/ (2*1)
x = (12 + √(144 - 176) )/ 2
x = (12 + √-32 )/ 2
√-32 = √(-1 *32) = √-1 * √32 = i * √(16 *2) = i*√16 *√2 = i*4*√2 = 4i√2
Where i is a complex number. Note the equation has two values. We shall include the second, that has negative sign before the square root.
x = (12 + √-32 )/ 2 or (12 - √-32 )/ 2
x = (12 + 4i√2 )/ 2 (12 - 4i√2 )/ 2
x = 12/2 + (4i√2)/2 12/2 - (4i√2)/2
x = 6 + 2i√2 or 6 - 2i√2
Recall equation (c):
y = 12 - x, When x = 6 + 2i√2, y = 12 - (6 + 2i√2) = 12 - 6 - 2i√2 = 6 - 2i√2
When x = 6 - 2i√2, y = 12 - (6 - 2i√2) = 12 - 6 + 2i√2 = 6 + 2i√2
x = 6 + 2i√2, y = 6 - 2i√2
x = 6 - 2i√2, y = 6 + 2i√2
Therefore the two numbers that multiply to 44 and add up to 12 are:
6 + 2i√2 and 6 - 2i√2
