4. Parker has saved $1,200 for him and his

Misha Larkins [42]

Answer:

18

Step-by-step explanation:

The formula for this is a x b = c x d where a is SR, b is FR, c is QR and d is PR. This will give us the equation 9(16) = 8(5x + 8); 144 = 40x + 64; 80 = 40x; x = 2. Now, plug this into PR which will be 5(2)+8 = 18. This is your answer.

3 0

3 years ago

You are jumping off the 12 foot diving board at the municipal pool. You bounce up at 6 feet per second and drop to the water you

NARA [144]

Answer:

When do you hit the water?

1.075 seconds after you jump.

What is your maximum height?

the maximum height is 12.5626 ft

Step-by-step explanation:

The equation:

h(t) = -16*t^2 + 6*t + 12

Is the height as a function of time.

We know that the initial height is the height when t = 0s

h(0s) = 12

and we know that the diving board is 12 foot tall.

Then the zero in h(t)

h(t) = 0

Represents the surface of the water.

When do you hit the water?

Here we just need to find the value of t such that:

h(t) = 0 = -16*t^2 + 6*t + 12

Using the Bhaskara's formula, we get:

$t = \frac{-6 \pm \sqrt{6^2 - 4*(-16)*12} }{2*(-16)} = \frac{-6 \pm 28.4}{-32}$

Then we have two solutions, and we only care for the positive solution (because the negative time happens before the jump, so that solution can be discarded)

The positive solution is:

t = (-6 - 28.4)/-32 = 1.075

So you hit the water 1.075 seconds after you jump.

What is your maximum height?

The height equation is a quadratic equation with a negative leading coefficient, then the maximum of this parabola is at the vertex.

We know that the vertex of a general quadratic:

a*x^2 + b*x + c

is at

x = -b/2a

Then in the case of our equation:

h(t) = -16*t^2 + 6*t + 12

The vertex is at:

t = -6/(2*-16) = 6/32 = 0.1875

Evaluating the height equation in that time will give us the maximum height, which is:

h(0.1875) = -16*(0.1875 )^2 + 6*(0.1875) + 12 = 12.5626

And the height is in feet, then the maximum height is 12.5626 ft

6 0

3 years ago

Reduce the fraction to lowest terms m^2/m^2-n^2

Softa [21]

Answer:

$\boxed{\bold{\frac{m^2}{\left(m+n\right)\left(m-n\right)}}}$

Step-by-step explanation:

Factor $\bold{m^2-n^2}$

$\bold{\left(m+n\right)\left(m-n\right)}$

Rewrite Equation

$\bold{\frac{m^2}{\left(m+n\right)\left(m-n\right)}}$

4 0

3 years ago

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Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 2.4 h, and Car B traveled the dis

Arte-miy333 [17]

One way to go about this is to first list everything we know in the form of variables. This will make it easier to see how these numbers correlate instead of trying to remember formulas to plug these numbers into.

TimeA = 2.4h (time of Car A to travel)
TimeB = 4h (time of Car B to travel)
SpeedA = SpeedB + 22mph (Speed of Car A)
SpeedB = SpeedA - 22mph (Speed of Car B)
Distance = x (the distance traveled by each car)

We are looking for SpeedA. How can we find this? Well, we know that speed multiplied by time is equal to distance, so let's start there.

SpeedA * 2.4h = x
(SpeedB + 22mph) * 2.4h = x
(2.4h * SpeedB) + 52.8miles = x

We also know that:
SpeedB * 4h = x

Since both of these equations are equal to x, we can combine them:
SpeedB * 4h = x = (2.4h * SpeedB) + 52.8miles
SpeedB * 4h = (2.4h * SpeedB) + 52.8miles
1.6h * Speed B = 52.8miles
SpeedB = 52.8/1.6 mph = 33 mph

SpeedA = SpeedB + 22mph = 33mph + 22mph = 55mph

Therefore, Car A was traveling at 55mph.

3 0

3 years ago

How can you divide 512 Dollars between two people So that one person can get $20 more than the other

Naya [18.7K]

Step-by-step explanation:

It is possible

One person will get 246 while the other will get 266 = 512

6 0

3 years ago

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