To find the perimeter of this blue figure, add together the shown lengths of the six sides.
The three measurements on the top have the LCD 4, so we combine 14 3/4, 4 2/4 and 8 2/4. The sum is 26 7/4, or 27 3/4, or 27.75.
The three measurements on the bottom share the LCD 5, so we can immediately combine them, obtaining 32 8/5, or 33 3/5, or 33.60.
Combining 27.75 and 33.60 results in 61.35, or 61 35/100, or 61 7/20.
The perimeter of the given figure is 61 7/20.
The question involves the concept & equations associated with projectile motion.
Given:
y₁ = 1130 ft
v₁ = +46 ft/s (note positive sign indicates upwards direction)
t = 6.0 s
g = acceleration due to gravity (assumed constant for simplicity) = -32.2 ft/s²
Of the possible equations of motion, the one we'll find useful is:
y₂ = y₁ + v₁t + 1/2gt²
We can just plug and chug to define the equation of motion:
<u><em>y = (1130 ft) + (46 ft/s)t + 1/2(-32.2 ft/s²)t²</em></u>
<em>(note: if you were to calculate y using t = 6.0 s, you'd find that y = 826.4 ft, instead of 830 ft exactly because of some rounding of g and/or the initial velocity)</em>
26 = 3x - 2 - 7x
26 + 2 = -4x
28 / -4 = x
x = -7
Best answer me please!
Answer:
it would be 103/25
Step-by-step explanation:
Answer:
b =21
Step-by-step explanation:
Since this is a right triangle, we can use the Pythagorean theorem
a^2 + b^2 = c^2 where a and b are the legs and c is the hypotenuse
20^2 + b^2 = 29^1
400 + b^2 =841
Subtract 400 from each side
b^2 = 441
Take the square root of each side
sqrt(b^2) = sqrt(441)
b =21
