Not sure if you mean to ask for the first order partial derivatives, one wrt x and the other wrt y, or the second order partial derivative, first wrt x then wrt y. I'll assume the former.
Or, if you actually did want the second order derivative,
![\dfrac{\partial^2}{\partial y\partial x}(2x+3y)^{10}=\dfrac\partial{\partial y}\left[20(2x+3y)^9\right]=180(2x+3y)^8\times3=540(2x+3y)^8](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cpartial%5E2%7D%7B%5Cpartial%20y%5Cpartial%20x%7D%282x%2B3y%29%5E%7B10%7D%3D%5Cdfrac%5Cpartial%7B%5Cpartial%20y%7D%5Cleft%5B20%282x%2B3y%29%5E9%5Cright%5D%3D180%282x%2B3y%29%5E8%5Ctimes3%3D540%282x%2B3y%29%5E8)
and in case you meant the other way around, no need to compute that, as
by Schwarz' theorem (the partial derivatives are guaranteed to be continuous because
is a polynomial).
I think it’s 25x if not send the equation answers
Answer:
-18+9k
Step-by-step explanation:
If you use the distributive property, you get:
(-3*6) and (-3*-3k)
If you simplify each of them you get:
-18+9k
Answer:
The value of nx is the ratio of the transformed x-coordinates to the original x-coordinates in each horizontal stretch. The value of ny is the ratio of the transformed y-coordinates to the original y-coordinates in each vertical stretch.
Step-by-step explanation:
PLATO
Mark me Brainliest plz, just a click of a button :)
Answer:
m∠C = 60°
Step-by-step explanation:
we know that sum of angles of a traingle is 18 degrees.
given
m∠A = 60°+α,
m∠B = 60°−α
we have to find m∠C
m∠A + m∠B + m∠C = 180
60°+α + 60° - α +m∠C = 180
+α and -α gets cancelled
120°+m∠C = 180
=> m∠C = 180° - 120° = 60°
Thus, measure of angle c is 60°.
