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rosijanka [135]3 years ago

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The net change in velocity during the given time interval is equal to -0.665.

<u>Given the following data:</u>

Initial time = 0.75 seconds.

Final time = 2.25 seconds.

Acceleration, $a(t) = sin(\frac{t^2}{3} )$

<h3>How to calculate the net change in velocity.</h3>

Since acceleration is the rate of change of velocity of an object, we would derive an expression for the velocity by differentiating with respect to time:

$V(t) = \frac{d}{dt} a(t)\\\\V(t) = \frac{d}{dt} (sin(\frac{t^2}{3} ))\\\\V(t) = cos( \frac{t^2}{3})(\frac{2t}{3})\\\\V(t) = \frac{2t}{3}cos( \frac{t^2}{3})$

Substituting the time interval, we have:

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V(t) = -0.665.

Read more on acceleration here: brainly.com/question/24728358

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